As you are a beginner in MATLAB, use MATLAB Onramp to learn the basics of the new language: https://matlabacademy.mathworks.com/details/matlab-onramp/gettingstarted Concerning your question, it will help to stud
The code implementing thewhileloop is in theex_while_loop_ML_stepfunction inex_while_loop_ML.c: /* Model step function */ void ex_while_loop_ML_step(void) { int32_T num_iter; boolean_T flag; boolean_T func_flag_0; /* MATLAB Function: '<Root>/MATLAB Function' */ func_flag_0 ...
조회 수: 1 (최근 30일) 이전 댓글 표시 Jalali2012년 10월 5일 0 링크 번역 MATLAB Online에서 열기 I have problem in the while loop below. Looks like the break doesn't work, because sometimes R<=0.3 and s becomes one or bigger. What I need ...
matlab中while()中条件终止循环的与break终止循环 matlab中while()中条件终⽌循环的与break终⽌循环 matlab中while()循环可以通过不同⽅式终⽌,但终⽌的⽅式不同在程序中运⾏产⽣错误: 其中,都是进⾏⼀次进⾏循环,然后跳出程序,但以下程序会在其他地⽅出差 1 a=0; 2 while 判断条件&&a...
clear n=input('输入成绩n=');m=60;while 1 if n>m && n<=100 fprintf('及格\n');elseif n<m && n>0 fprintf('不及格\n');else break;end n=input('输入成绩n=');end 我猜楼主是想实现这样的功能吧，while死循环是ctrl+c就可以退出来 这样可以么？
MATLAB循环结构:while语句P69范数待编 while语句的一般格式为: while条件 循环体语句 end 从键盘输入若干个数,当输入0时结束输入,求这些数的平均值和它们的和。 程序如下: sum=0; n=0; x=input('输入一个数字(end in 0):');whilex~=0sum=sum+x;...
参考代码：clcclear allclose alln = 1;diff = 1;counter = 1;%-- 附加的变量，用于观察中间量变化 --%diffm = [];nm = [];diffm(1) = diff;nm(1) = n;%---%while(diff>1e-6) n = n + 1; counter = counter + 1; diff = 1/n - 1/(n+1); diffm(n...
The MATLAB while loop is similar to a do...while loop in other programming languages, such as C and C++. However, while evaluates the conditional expression at the beginning of the loop rather than the end. do % Not valid MATLAB syntax statements while expression To mimic the behavior of...
The MATLAB while loop is similar to a do...while loop in other programming languages, such as C and C++. However, while evaluates the conditional expression at the beginning of the loop rather than the end. do % Not valid MATLAB syntax statements while expression To mimic the behavior of...
1、不建议在if里面给变量赋值。if lambda1(m,1)>=0&&lambda1(m,1)<=1lambda2=lambda1(m,1);end 如果if不成立，lamda2将不存在。2、很多人会想当然的说if肯定成立啊，等等理由 建议对if是真正成立进行验证。比如：if lambda1(m,1)>=0&&lambda1(m,1)<=1lambda2=lambda1(m,1);disp(...