百度试题 结果1 题目12. Which of the numbers below are NOT factors of 16? 3(1) 1 and 8(2) 2 and 4(3) 6 and 32(4) 8 and 16 相关知识点: 试题来源: 解析 3 反馈 收藏
Which of the following numbers has factors of 2, 4, 6, and 8? A. 12B. 54C. 72D. 80相关知识点: 试题来源: 解析 C 2 and 4 are factors of 8, so we need to find the number that only has both 6 and 8 as factors.反馈 收藏 ...
英文数学题补充一下:13s:13,26,39.change word:5 is a factor of 10. 10 is a multiple of 51.a)show that 13 is a factor of 13 by counting by 13s starting at 0b)which whole numbers are factors of themselves?explain.2.a)show that 1 is a f
On Numbers which Contain no Factors of the Form P (kp + 1)S. Sivasankaranarayana Pillai
The factors of 49 are1,7 , and49, Since 49 has 3 factors, it has a prime number of factors. 下列哪个数的整数因子的个数是质数( ). A.6 B.12 C.36 D.49 49的因数是1,7和49,因为49有3个因数,所以它的因数个数是质数. 故选D.结果...
百度试题 结果1 题目4. Which one of the following numbers has 4 and 6 as its factors?I(1)12(2)16(3)18(4)20 相关知识点: 试题来源: 解析 1 反馈 收藏
A prime number is a positive integer having exactly two factors. If p is a prime, then the only factors it can have are 1 and p. Any number that does not fall into this category is said to as a composite number, meaning it may be factored into other posi
Which pattern of numbers is exponential?Answer and Explanation: An exponential pattern of numbers is described using an exponential function. You candescribe such a pattern of numbers by b^n where n = 1,2,3,... and b is some number. Note that you get to the next number in the series...
aThe total elephant population has fallen to less than half a million and the numbers will continue to dwindle as long as they are under threat. There are several factors which are playing simultaneous roles in causing such wide spread threat to the very survival of the elephant species. 总大...
10 is a multiple of 51.a)show that 13 is a factor of 13 by counting by 13s starting at 0b)which whole numbers are factors of themselves?explain.2.a)show that 1 is a factor of 8 by counting by 1s starting at 0b)which whoe numbers have 1 as a factor?explain.3.rewrite each ...