In this application nZ = 60 and nE = 2000 I tried to: (1) have the bigger loop inside, (2) sweep rows for a fixed column. To do that, I had to transpose some of previously defined matrices. Note that the row with BB2(j,k) = profit... is there because I need to save the ...
You select rows 1:15000 from column 2 of your data matrix and transpose it (using '), and store it in data. Before this operation, data is some N*M matrix with N at least 15000 and M at least 2, and after the assignment, data is a 1x15000 matrix...
Let's say MathWorks decides to create a MATLAB X release, which takes a big one-time breaking change that abandons back-compatibility and creates a more modern MATLAB language, ditching the unfortu...
Line 211: This line calculates the ‘ssX’ by multiplying the transpose of weight and bias vector with itself. worker.ssX = worker.WB' * worker.WB; Next, to understand the value returned bycalcLib.getwbin the line 195 oftrainbr.mfile, navigate to the...
In[8]: x = np.array([[1,2,3],[4,5,6],[7,8,9]]) In[7]: xT = np.transpose(x) #take transpose of the matrix In[8]: xT Out[8]:xT = ([[1,4,7],[2,5,8],[3,6,9]]) In[9]:n = diag(range(1,4)) #defining a diagnol matrix In[10]: n Out[10]:n = ([...
Hi I saw this in Matlab document: ThemeCopy function obj = DocPolynom(c) % Construct a DocPolynom object using the coefficients supplied if isa(c,'DocPolynom') obj.coef = c.coef; else obj.coef = c(:).'; end end What does c(:).' mean? Is .' the transpose of each element?
Transpose a matrix via pointer in C I'm trying to transpose a matrix in C while passing the matrix to a function and return a pointer to a transposed matrix. What am I doing wrong in the second while loop? in main create matrix transpos... ...
(*,fmt) transpose(spread([1,(0,i=2,rank(A))],2,rank(A))) write(*,'(a)') 'eoshift(' // & 'spread([1,(0,i=2,rank(A))],2,rank(A)), 1-(' // & '[(i,i=1,rank(A))] +' // & 'eoshift([rank(A)-Ndim,(0,i=2,rank(A))],1-Ndim) +' // & 'eoshift(...
The derivative is obtained by just another application of the chain rule: If we want to take gradients, we just transpose the expression and get Note that the right hand side is indeed vector in and hence, can be reshaped to a tupel of an matrix and an vector. A final remark: the...
aThe important basic matrix operations are addition and subtraction, multiplication, transpose, powers, and the so-called array operators given in Table A.1 apply to matrices. We will not discuss matrix division, but be aware that MATLAB has a left and right-matrix division capability. 正在翻译...