Magnification of object for mirrors: it is defined as the ratio of the height of the image and the height of the object. Magnification of the object for plane mirror is one because the height of the image is sam
The lens formula gives a relationship between the focal length of the lens and the object and image distances from the lens. It is expressed by the formula: 1v−1u=1f, where: v is image distance u is object distance f ...
For formation of virtual image in convex lens both n and v are negative [Fig.]. So linear magnification m is positive. The image is erect. In case of concave lens both n and v are negative, [Fig.]. So linear magnification m is positive. So the image is erect. So we can say that...
(a) The linear magnification of a concave lens is always positive. Why? (b) The linear magnification of a convex lens may be positive or negative. Why ? View Solution An object is placed at the focus of concave lens having focal length /. What is the magnification and distance of the ...
Prime lenses have a fixed focal length lens. That means you’re locked into shooting at a single focal length — no zooming and no magnification. “If you want to get into photography professionally, I would suggest picking a prime focal length that you like, that you’re comfortable with,...
Identify the given quantities: the object distance from the lens (unknown), the image distance from the lens (3.0 m), and the magnification (m = -2, since the image is twice the size and inverted). Use the magnification formula for lenses, which is m =...
- Here, v is the image distance and u is the object distance. 3. Express Image Distance in Terms of Object Distance: - From the magnification formula, we have: −vu=14 - Rearranging gives: v=−14u 4. Use the Lens Formula: - The lens formula is given by: 1f=1v−1u - Subst...
If you want tophotograph planetsin detail, a high magnification, large aperture telescope like a Schmidt-Cassegrain is tough to beat. These telescopes can be mounted to a tracking equatorial mount, to precisely track the movement of the planets across the sky. ...
What is the magnification of the image? Suppose that you have a converging lens that produces a real image of a small object. The image is at a distance of 150 cm to the left of the lens and the object is at a distance of 75 cm to the right of the lens. Please kindly show your...
We know that cameras see objects in a similar manner to the human eye. For instance, the nearer an object is to the lens, the larger it appears. An illustration of this is how a straight road appears to taper off into the distance even though its width does not actually change. ...