log(cosh(x)-1) is not the same as log(cosh(x-1)). The argument of cosh is x in the original problem, you wrote(x-1). You made errors with the parentheses in the solution. Somehow you wrote the correct derivative, but the marking scheme is not correct.May...
Prove the identity. cosh(-x) = cosh x Prove the identify. \cosh(-x) = \cosh(x) (This shows that cosh is an even function.) \cosh(-x) = \frac{1}{2}[ \: +e^{-(-x)}] = \frac{1}{2} (+e^{x}) Find the derivative. G(x) = \sinh^{2}(x) ...
How to find c in an anti-derivative? What is Anti-derivative of \frac{1}{y^2}? What is the anti-derivative of 2 sin x - tan 3x? What is the anti-derivative, R(t) for this equation? What is the anti-derivative of \sqrt{\cosh^{2}(x)}?