The proper way to stay out of trouble is to avoid dereferencing a NULL pointer to create a reference. Here's an automated way to accomplish this. template<typename T> T& deref(T* p) { if (p == NULL) throw std::invalid_argument(std::string("NULL reference")); return *p; }...
std::barrier<_No_completion_function> my_barrier5; };intmain(){return0; } Am I overlooking an obvious way of declaring astd::barrierwith no completion function? Related regarding N4861, but ultimately not helpful:
While it is working if to specify NOEXCEPT template argument explicitly (like fn<float, true|false>) it seems that only the deduction from an argument is not working. I don’t know if there is a C++ standard for that, if that supposed to work, but i just don’t see why not (and...
void TestFunctions::simpleLambda() { bool sensitive = true; std::vector<int> v = std::vector<int>({1,33,3,4,5,6,7}); sort(v.begin(),v.end(), [sensitive](int x, int y) { printf("\n%i\n", x < y); return sensitive ? x < y : abs(x) < abs(y); }); printf("s...
"[given] a type TR that is a reference to a type T, an attempt to create the type “...
Classes, just like structs, can be PODs even though the standard term is POD-struct for both cases Just like in the case of aggregates, it doesn't matter what static members the class has Examples: structPOD{intx;chary;voidf(){}//no harm if there's a functionstaticstd::vecto...
void func3(std::vector<int>& v) { std::for_each(v.begin(), v.end(), [](int) { /* do something here*/ }); } Lambda functions are just syntactic sugar for anonymous functors. Return types In simple cases the return type of the lambda is deduced for you, e.g.: void fu...