$$\begin{align} \sin^{2} \theta+ \cos^{2} \theta &= 1 \\[0.2cm] 1+\cot^{2} \theta &= \csc^{2} \theta \\[0.2cm] 1+\tan^{2} \theta &= \sec^{2} \theta \\[0.2cm] \tan \theta &= \frac{\sin \theta}{\cos \theta} \\[0.2
What is sin(theta) given tan(theta) = 12/5? Pythagorean Theorem and Trigonometric Ratios Pythagorean theorem In a right triangle, the square area of the hypotenuse side is always equal to the sum of the square areas of the adjacent and opposite sides individually. ...
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What is sqrt((1 + sin theta)/(1 -sintheta)) equal to ? 01:16 If 7 cos^2 theta +3 sin^2 theta =4 and 0 lt theta lt pi//2, what is th... 01:15 The value of (tan 27^@ + cot 63^@)/(tan 27^@ (sin25^@ + cos65^@)) 02:02 If cos theta ge 1//2 in the fir...
What is SOH-CAH-TOA? The sine of one of the angles of a right triangle (often abbreviated “sin”) is the ratio of the length of the side of the triangle opposite the angle to the length of the triangle’s hypotenuse. The cosine (often abbreviated “cos”) is the ratio of the leng...
{eq}x^{2}+y^{2}=r^{2} {/eq}) or an r coordinate for the radius and a {eq}\theta {/eq} coordinate for the angle relative to what would be the positive x-axis (the equation of the figure being {eq}x^{2}+y^{2} = (r\, cos\theta)^{2} + (r\, sin\theta)^{2} {...
If \cos x= \frac{2}{3} and x is in quadrant IV, find \tan(\frac{x}{2}),\sin(\frac{x}{2}),\ and\ \cos(\frac{x}{2}). Use the given information to find the quadrant in which \theta lies. \cot \theta 0 and \cos \theta 0 a) Quadrant II\\b) Quadrant IV \\c) Qu...
sinTheta0 = Math.sin(theta0); x = sinPhi0 * cosTheta0 * radius; y = cosPhi0 * radius; z = sinPhi0 * sinTheta0 * radius; /*** The line above converted the UV coordinates to spherical coordinates ***/ /*** The lines below offset the tooltips from the environment sphere ***...
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$$\begin{aligned} \sigma _b = \cos (2\Delta \Theta )\sigma _z + \sin (2\Delta \Theta )\sigma _x = \left( \begin{matrix} \cos (2\Delta \Theta ) & \sin (2\Delta \Theta ) \\ \sin (2\Delta \Theta ) & -\cos (2\Delta \Theta ) \end{matrix}\right) , \end{aligned...