Hello community, I saw a contest named Codeforces Round X in the upcoming contest list, can anybody tell what is that??? If it is a new type of round then I am really excited for it.
Vedanta is a philosophy handed down by the Vedas, the oldest Holy Scriptures in India. It teaches that our real nature is divine. God is our innermost Being, an underlying reality in everything that exists. Truth is universal and religion is the search for Being, the search for God within...
codeforces 1474 E - What Is It? (构造) 题目链接:https://codeforces.com/contest/1474/problem/E开始以为答案是 12+22+...+(n−1)212+22+...+(n−1)2 看题解以后发现没有这么简单。。因为每次交换必定会让一个位置还原,所以每个位置都要尽量和当前没有还原位置中的最远的位置交换, 也就是把...
The situation is similar on the competitive coding platform Codeforces. GPT-4o only scores in the 11th percentile, while the full o1 model scores in the 89th percentile. The story is largely the same with o3-mini. On various benchmarks, o3-mini with low reasoning effort matches or exceeds...
As Valerie is not good at mathematics, she asked you to help her to find out the total amount of crucians that she can consume for dinner. We should remind you that while eating one crucian Valerie uses exactly one row of teeth and the viability of each tooth from this row decreases by...
To kickstart your journey in competitive programming, start by learning a programming language of your choice. Then dive into algorithms and data structures. Practice solving problems on platforms like Codeforces, Topcoder, or LeetCode. Join online communities or participate in contests to gain experi...
You all know the Dirichlet principle, the point of which is that ifnboxes have no less thann + 1items, that leads to the existence of a box in which there are at least two items. Having heard of that principle, but having not mastered the technique of logical thinking, 8 year old...
简单构造,推了一会就推出来了,无法理解为啥有2500分,感觉还不如一些1900的题( #include <bits/stdc++.h>usingnamespacestd;intmain() {intt; scanf("%d", &t);while(t--) {intn; scanf("%d", &n);longlongans =0;for(inti =1; i <= (n +1) /2; i++) ...
传送门:https://codeforces.com/problemset/problem/1474/E 显然是道构造题 显然我们考虑反向 由一个 identity permutation 回推至最初的数列 考虑贡献 最大为 n-1 显然只能出现一次这样的操作 再考虑 n-2 发现至多两次 以此类推 就很好构造出一组解 #include <bits/stdc++.h> using namespace std; #define...
DeepSeek claims its LLM beat OpenAI's reasoning model o1 on advanced math and coding tests (AIME 2024, MATH-500, SWE-bench Verified) and earned just below o1 on another programming benchmark (Codeforces), graduate-level science (GPQA Diamond), and general knowledge (MMLU). ...