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4NH3+3O2-->6H2O + 2N2. ( deltaH1 = -1516 kJ) 2. 2H2+O2 --> H2O ( deltaH2 = -572 kJ) What is the molar enthalpy of formation for ammonia? A. -100kJ B.-50kJ C. 50KJ D.100KJ I'm not sure how I would apply the product - reactant equation here or rearrange the...