结果1 题目What is the result of 9 divided by 3? A. 2 B. 3 C. 6 D. 9 相关知识点: 试题来源: 解析 B。本题考查除法运算,9 除以 3 的结果是 3,A 选项 2 错误,C 选项 6 是 9 减去 3 的结果,D 选项 9 不符合。反馈 收藏
586 divided by 647 step-by-step guide Step 1 The first step is to set up our division problem with the divisor on the left side and the dividend on the right side, like we have it below: Step 2 We can work out that the divisor (647) goes into the first digit of the dividend (...
--What is 12 divided ___ 3? --___. A. by; 4 B. with; 15 C. by; 36 D. from; 9 相关知识点: 试题来源: 解析 A 【详解】试题分析:句意:12除以3是多少?是4。by介词,被,divide by,被……分割,故选A。 考点:考查介词的用法。
是4。by介词,被,divide by,被……分割,故选A。 分析总结。 一题一题找答案解析太慢了下载作业精灵直接查看整书答案解析立即下载练习册系列答案学习报快乐寒假系列答案寒假作业广州出版社系列答案快乐寒假河北科学技术出版社系列答案寒假作业安徽少年儿童出版社系列答案寒假乐园北京教育出版社系列答案尚书郎精彩假期寒假篇...
解析 【解析】句意:12除以3是多少?是4。by介词被,divide by,被..分割,故选A。 结果一 题目 --What is 12 divided ___ 3? --___.A.by; 4B.with; 15C.by; 36D.from; 9 答案 A 结果二 题目 --What is 12 divided ___ 3? --___.A. by; 4B. with; 15C. by; 36D. from; 9 答案...
What is 51 divided by 3? Division by 3 When dividing a whole number by 3, there's a trick to tell if that number will divide evenly. Look at the number you are dividing and add up its digits. If the sum of those digits is a multiple of 3, then the entire number is divisible ...
--What is 12 divided ___ 3? --___. A. by; 4B. with; 15C. by; 36D. from; 9 试题答案 A 【解析】 试题分析:句意:12除以3是多少?是4。by介词,被,divide by,被……分割,故选A。 考点:考查介词的用法。 一题一题找答案解析太慢了下载作业精灵直接查看整书答案解析立即下载 练习册系列...
What is 126 divided by 3? Division We perform mathematical division all the time. A good example is determining the number of courses to graduate with a degree. If an engineering program requires 126 credits for graduation and each course is 3 credit hours, how many courses are required to ...
百度试题 结果1 题目)3. -What is eight dividedtwo?Four.A.upB.inC. intoD.by 相关知识点: 试题来源: 解析反馈 收藏
1 0 0 0 3 8 5 - 0 3 8 - 0 3 8 5 - 0 3 8 5 So, what is the answer to 385 divided by 1000? If you made it this far into the tutorial, well done! There are no more digits to move down from the dividend, which means we have completed the long division problem...