The first number, 840, is called the dividend. The second number, 842 is called the divisor. What we'll do here is break down each step of the long division process for 840 divided by 842 and explain each of them so you understand exactly what is going on. 840 divided by 842 step-...
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3.When a number is divided by 7,it gives a quotientof 4 with a remainder of 6.What is the number?(A)17(B)168(C)34(D)31(E)463. When a number is divided by 7,it gives a quotient of 4 with a remainder of 6.What is the number? (A)17 (B)168 (C)34 (D)31 (E)46 ...
百度试题 结果1 题目What is the quotient of 48 divided by 6? A. 8 B. 9 C. 10 D. 11 相关知识点: 试题来源: 解析 A 二、填空题
281 divided by 331 step-by-step guide Step 1 The first step is to set up our division problem with the divisor on the left side and the dividend on the right side, like we have it below: Step 2 We can work out that the divisor (331) goes into the first digit of the dividend (...
What is the least possible remainder when an even number is divided by 7?( ) A. 0 B. 1 C. 5 D. 6 相关知识点: 试题来源: 解析 A When 14 (or any other even multiple of 7) is divided by 7, the remainder is 0.反馈 收藏 ...
What are the quotient and remainder when 44 is divided by 8? What is the quotient and remainder of { 4x^3-2x^2+x+1 } divided by x+2? What are the quotient and remainder when 30 is divided by 7? What are the quotient and remainder when 2 x^3 - 9 x^2 + 11 x - 6 is div...
What is 70 divided by 6? Division with Remainders Dividing whole numbers is a basic mathematical operation. Sometimes, a number divides evenly by another number but other times, you are left with a remainder. For example, 20 / 4 = 5, but 20 / 3 = 6 R.2. ...
C. 2D. 6相关知识点: 试题来源: 解析 D 结果一 题目 What is the remainder when 1414146 is divided by 7( ).A.0B.1C.2D.6 答案 D相关推荐 1What is the remainder when 1414146 is divided by 7( ).A.0B.1C.2D.6 反馈 收藏
Step 8 Next, we will subtract the result from the previous step from the third digit of the dividend (58 - 0 = 58) and write that answer below: 00 63058 -0 58 -0 58 So, what is the answer to 58 divided by 630? If you made it this far into the tutorial, well done! There ...