What is the total number of integers between 100 and 200 that are divisible by 3? (分数:5.00) A. 33 √ B. 32 C. 31 D. 30 E. 29 相关知识点: 试题来源: 解析 解析:对于区间[a,b]中有多少个数能够被数n整除,计算方法如下:第一步:把b往小里凑。找到最近的n的倍数,记为r;比如例题中...
What is the least positive integer that is divisible by each of the integers 1 through 7, inclusive ?() A.420 B.840 C.1,260 D.2,520 E.5,040 相关知识点: 试题来源: 解析 A [解析] 该题也即让考生求1,2,3,4,5,6和7这7个数的最小公倍数。根据最小公倍的求解公式可得其最小公...
What is 60 divisible by? Answer and Explanation: The number 60 is divisible by 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60. The numbers that can divide 60 (with remainder = 0) can also be called... Learn more about this topic: ...
Data Sufficiency 试题详情 题目: Ifkis a positive integer, what is the remainder whenis divided by 10 ? (1)kis divisible by 10. (2)kis divisible by 4. 选项: 答案: B
What is the least positive integer that is divisible by each of the integers 1 through 7, inclusive ?() A.420 B.840 C.1,260 D.2,520 E.5,040 点击查看答案&解析手机看题 你可能感兴趣的试题 单项选择题 For any positive integer n, n>1, the "length" of n is the number of positive...
百度试题 结果1 题目d)If a number is divisible by 9, by what other number is it also divisible? 相关知识点: 试题来源: 解析 Thenumbermustalsobedivisibleby3. 反馈 收藏
百度试题 结果1 题目What is the value of X so that the 4-digit number 37XX is divisible by 12?X的值是多少才能使4位数字37XX被12整除? A: DB: 2 C: 4 D: 6 E: 8 相关知识点: 试题来源: 解析 C略 反馈 收藏
If k is a positive integer, what is the remainder when is divided by 10 ? (1) k is divisible by 10. (2) k is divisible by 4. 选项: 答案: B 提问列表 提问 提问: 没有什么思路,希望老师点播。 解答: 点赞0 阅读746 解答: sysadmin 提问: 没有什么思路,希望老师点播。 解答: ...
What is the greatest common factor of the positive integers j and k ? (1) k = j + 1 (2) jk is divisible by 5. 选项: 答案: A 提问列表 提问 提问: 不会。。无思路。。。希望老师讲解。。 解答: 点赞0 阅读1293 解答: sysadmin 提问: DS题一个条件能解决问题的定义到底是怎样的呢...
What is the probability of a random generated zip code being divisible by 5?Question:What is the probability of a random generated zip code being divisible by 5?Probability of Random EventsIn order to find the probability of a random event occurring, we need to define how that...