I'm using Microsoft Office 365. I've discovered the DATEDIF formula in this forum, but it's not to working for me. I've tried several variations and get the #NAME? error. Examples: DATEDIF(AB2,AA4,D) DATEDIF("11/09/2020","04/01/2021",D) DATEDIF(AB2,"04/01/2021",D) DATEDIF(...
I want the new cell to have the format "X years Y months" with the number of fulfilled years and months. Cannot get the DATEDIF solution to work (Could it be because of a swedish version of excel - end what is then the right command in swedish?) Anyone who could help!?
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What did Ethbell do when she was 68?对非法持有属于国家秘密的文件、资料和其他物品的，以及非法持有、使用专用间谍器材的，国家安全机关可以依法对其（）进行搜查；对其非法持有的属于国家秘密的文件、资料和其他物品，以及非法持有、使用的专用间谍器材予以没收。
From currency conversion to data filtering, do more with Zoho Sheet's nine new functions: CURRENCY FILTER TEXTJOIN MAXIFS MINIFS IFS UNIQUE XOR DATEDIF Learn more about these functions Feb Zoho Sheet 5 - Evolving beyond traditional spreadsheets Zoho Sheet has gone through a from-the-scrat...
Errors: Download thezipped Excel Formula Errors file. The zipped file is in xlsx format, and does not contain any macros. ERROR.TYPE: To follow along with the ERROR.TYPE video, you can download theERROR.TYPE function file. The zipped file is in xlsx format, and does not contain any macr...
datedif for years > 1900 I try to user datediff for people who lived before 1/1/1900; this does not work as excel considers 1/1/1900 as day one. How can I get the result for someone who lived say from 1/3/1600 to 5/5/1665 ??
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=(DATEDIF(E26,F26,"Y")+DATEDIF(K26,$L$2,"Y"))&" Y "& (DATEDIF(E26,F26,"YM")+DATEDIF(K26,$L$2,"YM"))&" M" This is giving me months greater than 12. How do I correct this? Embry3894 You add the years of both periods and the months of both periods s...
=DATEDIF(C3,TODAY(),"m") It works in my sheet when i enter C3 without " ". OliverScheurich, Thanks for looking into it, I tried without "" also with , and ; but I was keeping on getting the error. When I changed the date system to 1904 in the advance option, then it works...