解法一 BFS 每次水壶都有三个操作:加满水、清空水、相互倒。 Python3代码 class Solution: def canMeasureWater(self, x: int, y: int, z: int) -> bool: # solution one: BFS from collections import deque queue = deque([[0, 0]]) visited = set([(0, 0)]) while queue: cur_x, cur_y...
解法一 BFS 每次水壶都有三个操作:加满水、清空水、相互倒。 Python3代码 class Solution: def canMeasureWater(self, x: int, y: int, z: int) -> bool: # solution one: BFS from collections import deque queue = deque([[0, 0]]) visited = set([(0, 0)]) while queue: cur_x, cur_y...
365. Water and Jug Problem (GCD or BFS) TBC https://leetcode.com/problems/water-and-jug-problem/description/ -- 365 There are two methods to solve this problem : GCD(+ elementary number theory) --> how to get GCF, HCD, BFS Currently, I sove this by first method 1. how to comput...
https://doi.org/10.15414/JMBFS.2017.6.5.1181-1187 Anyanwu C NS and MA (2011) Soil bacterial response to introduced metal stress. Int J Basic Appl Sci 11:73–76 Sidkey N, Moustafa Y, Arafa R et al (2016) Corrosion resistance and antimicrobial activity of extra- and intracellular Fe(II...
Operations − These include; an action of putting water into a jug transferring water from one jug to another or taking water out of a jug. In the process of function activation each operation leads to the formation of a new state. BFS Approach − It is used in the game or simulation...
输出: False 思路 懒得整BFS和DFS,就只能靠数学方法做了。通过裴蜀定理,若xy的最大公约数是z的因子,就代表可以倒出所需的水。 代码 publicintgcd(intx,inty){if(y ==0) {returnx; }intr=x % y;returngcd(y, r); }publicbooleancanMeasureWater(intx,inty,intz){if(x ==0&& y ==0) {return...