Figure 2.10 illustrates a simple circuit containing an (independent) current source, is , two resistors, and a controlled voltage source, whose magnitude is controlled by the current i1. Thus, i1 determines two voltages in the circuit, the voltage across R1 via Ohm’s law and the controlled...
Similarly, assume acurrent sourcewith the value I and internal resistance r. Now according to theOhm’s law, thevoltageacross the source can be calculated as Thus, the voltage across the source, when its terminals are open, is V.
Low voltage current mirror and CTAT current source and method A low voltage CTAT current source includes a bipolar transistor connected across two series-connected resistors. A voltage developed across the resistors turns on the transistor, making the current through the resistors CTAT. A second ...
connected in series with the load impedance so that current flows through the resistor and the load impedance. The instrumentation amplifier receives the input voltage at its inverting input and receives a load voltage representing the voltage across the load impedance produced by the load current at...
The transistor 27 and further transistor 29, 30 form a current switch in which coincidence of negative inputs to 29 and 30 cause the normally off transistor 27 to turn on, and to produce the voltage drop across the resistor 36 and an increase in current flow in transistor 18. This higher...
As the circuit shown in figure (a), the volt-ampere characteristics of the nonlinear resistors are shown in figure (b), the current source iS =1A, then the voltage across the current source u=[填空1]V. 参考答案:1、2 点击查看答案&解析进入小程序搜题 你可能喜欢 ()主要用来表达机件上倾斜...
ORCAD16.6 仿真就显示Voltagesource and/orinductorloopinvolvingL_L9. You may break theloopby adding a series resistance 这是我的电路图,仿真就显示Voltagesource and/orinductorloopinvolvingL_L9. You may break theloopby adding a series resistance。请各位大虾相助。
The DC Voltage Source block represents an ideal voltage source that is powerful enough to maintain specified voltage across its terminals regardless of the current flowing through the source. You specify the output voltage by using the Constant voltage parameter, which can be positive or negative. ...
Vccs is the voltage across the constant current source and IRe1= Iref to a close approximation, and Vbe can be taken as 0.6 to 0.65V: Rd = (Vss – (Vccs + Vbe(Q1)+ VRe1)) / Iref4 Vce is the desired maximum voltage across Q2, and at no load. IRe2isapproximately equal to Iref...
If current supplied to the load decreases, the internal op amp of the LM4041 will readjust the correct voltage across Rs by draining more current from the base of the transistor. 3.3 Current Source with Series Voltage Reference A series voltage reference can be used to increase the accuracy ...