Also, is there any way of generalizing a function which can receive a pointer and store it in a void pointer and by using that void pointer, can we make a generalized function? for e.g.: void abc(void *a, int b) { if(b==1) printf("%d",*(int*)a); // If integer pointer i...
#include<stdio.h>voidmain(){intn=30;int*ptrn=&n;floaty=10.7,*ptry=&y;void*Pv;//declaration of void pointersPv=ptrn;//assigning ptrn to pvclrscr();printf("*(int*)Pv = %d\n",*(int*)Pv);//dereferencing pvPv=ptry;//assigning ptry to pvprintf("*(float*)Pv= %f\n",*(float...
1 A pointer to void may be converted to or from a pointer to any object type. A pointer to any object type may be converted to a pointer to void and back again; the result shall compare equal to the original pointer. A void expression has no value (although it may have side effect...
Because the variety of pointer in computer memory is a address number in essence, it costs 4 bytes space to be stored in memory. Given that the calculations between pointers and different explaination between references and dereferences, the designer of C language makes the regulations for pointer...
Pointer Arith In GNU C, addition and subtraction operations are supported on pointers to void and on pointers to functions. This is done bytreating the size of avoidor of a function as 1. so...sizeof(void *) = sizeof(char *) = 4. ...
Pointer Arith In GNU C, addition and subtraction operations are supported on pointers to void and ...
In computerprogramming, when void is used as a function return type, it indicates that the function does not return a value. When void appears in a pointer declaration, it specifies that the pointer is universal. When used in a function's parameter list, void indicates that the function take...
Note that the parentheses that follow the function name are not optional in any case. Void as a Pointer Declaration The third use of void is a pointer declaration that equates to a pointer to something left unspecified, which is useful to programmers who write functions that store or pass p...
Returns:apointertovoidifsuccessful,orNULLifnot.这段说明很显然是来自Quick C的某个帮助文档的，成功就...
To prevent an error, an explicit cast to the actual function type (void (*)(int)) is required in C++. It should be noted that converting avoid *to a function pointer in both C and C++ is considered undefined behavior. However, if thevoid *was converted from a compatible function pointer...