Since (2, 0) and (3, 0) are the x-intercepts of the given parabola, (x - 2) and (x - 3) are the factors of the equation of the parabola. So the equation of the parabola is of the form: y = a (x - 2) (x - 3) ... (1) Its y-intercept is given to be (0, 6)...
This problem has been solved! You'll get a detailed solution that helps you learn core concepts.See AnswerQuestion: explain how to get x-intercepts from vertex form explain how to get x-intercepts from vertex form Here’s the best way to solve it. Solution Share Step 1 View the full ...
Finding X-intercept(s): Step 2:To solve for the x-intercept(s), equate y=0 and solve for x. (x1,0),(x2,0) x2−9=0 x2=9 x=+3,−3 X-intercepts=(+3,0)(−3,0) Finding the Vertex: Step 3:Change the given equation into the perfect square form. ...
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Let's find the vertex first.In this case we can consider the equation to be in the formf(x)=a(x-h)2+k or we can use the form f(x)=ax2x+bx+c.Either form will work and whichyou find to be the easiest will probably depend on you.We'll use the first form so we can get ...
What is a in the vertex form of a parabola? What is x in the vertex form of a parabola? What is the vertex form of a parabola? Find the vertex of the parabola f(x) = -x^2 - 4x + 1 How do you find the x-intercepts of a parabola in vertex form? Write the equation of a ...
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The vertex of a parabola is a point at which the parabola makes its sharpest turn. The vertex of f(x) = ax^2 + bx + c is given by (-b/2a, f(-b/2a)). Learn how to find vertex of a parabola from different forms like standard form, vertex form, and inter
We can use the same method to find the vertex by changing the form of the equation into the vertex form which is a(x−h)2+k, where (h,k) is the vertex. Answer and Explanation:1 The equation we have is −2x2+6x+1=0
Quadratics vertex form Quadratics vertex form September 6, 2016