这个错误的直接原因是 Verilog 不支持 Data_i[i*8-1:i*8-8] 这种语法。如果把向量的位选取写成 v...
这个是用c语言写电路。那个for里面的i需要定义为genvar i；另外从你写的逻辑看，你是希望那个shift_reg不断的变化，但是你这么写的话。系统会认为是一个组合逻辑，所以会立刻计算出结果。你需要写成时续逻辑的电路，用always @（posedge clk）begin ...end ...
在always块里赋值的必须是reg型，不能是wire型。
由於struct s_vpi_systf_data規定自訂的C function的signature必須為PLI_INT32 (*calltf)(PLI_BYTE8 *),所以依照其規定宣告hello_world型別。 24行 // associating C function with new verilog system task // you can use your favorite function name void register_my_systfs() { s_vpi_systf_data t...
Assign C=A+B; C的最高位用来存放进位。 6、关系运算符: 关系运算符:<,>,<=,>= 和算术操作符一样,可以进行有符号和无符号运算,取决于数据类型是reg,net还是integer。 7、相等运算符:==,!= 注意:===和!==是不可综合的。 可以进行有符号或无符号操作,取决于数据类型 ...
///always @ (posedge ph1) begin //if(cont == 15)//PM_11[0] = 10'd100;//end 上面这段可以全删了。加到下面去：// Memory Write Block // Write Operation : When we = 1, cs = 1 always @ (posedge ph1)begin : MEM_WRITE if(cont == 15)PM_11[0] = 10'd100;else ...
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39、60; r = $fgets(string, n, file);V2K does not support a maximum count "n" of characters to read. Inputin V2K always terminates at end of line and then string assignment to thetarget is done.Fileio's $gets is not directly supported in Verilog 2001. Theoperation can ...
// clk is on the LHS and the not of clk forms RHS always #10 clk = ~clk; // y is the LHS and the constant 1 is RHS assign y = 1; // f is the LHS, and the expression of a,b,d,e forms the RHS assign f = (a | b) ^ (d & e); ...
module module_name//模块名称 (port_list);//输入输出信号列表 //说明 reg //寄存器 wire//线网 parameter//参数 input//输入信号 output//输出信号 inout//输入输出信号 function//函数 task//任务 . . .//语句 Initial statement Always statement ...