Verilog-检测输入序列能否被3整除 目录 题目 编程思路 代码 仿真波形 题目 输入一个序列,最新输入的数字为最低位,如果当前序列能被3整除,输出1,否则输出0。 例如:输入1010_1111,对应1,2,5,10,21,43,87,175,因此输出为:0000_1010. 编程思路 代码 `timescale 1ns / 1ps module sequence_divide_by_3(
Remainder_0 : Remainder_2; Remainder_2: next_state = data ? Remainder_2 : Remainder_1; default : next_state = Remainder_0; endcase end assign divide_by_3 = (((state == Remainder_0) && (~data)) || ((state == Remainder_1) && (data)))?1'b1:1'b0; endmodule ...
2、divide-by-3 counter *** module divide_by_3 ( input wire clk_in , //Input Clock input wire reset , // Reset Input output wire clk_out // Output Clock ); //---Internal Variables--- reg [1:0] pos_cnt; reg [1:0] neg_cnt; //---Code Start--- // Posedge counter always...
We will now extend the clock Divide by 3 code to division by any odd numner. As earlier, we again have to keep a count of the number of the rising and falling edges. Then we use a clever mathematics to drive clock that is divided by an odd number. Problem - Write verilog code ...
Verilog Examples - Clock Divide by 2 A clock Divider has a clock as an input and it divides the clock input by two. So for example if the frequency of the clock input is 50 MHz, the frequency of the output will be 25 MHz. In other words the time period of the outout clock will...
3. 解释 模块声明:定义了一个名为 single_ended_to_differential_clock 的模块,它有一个单端时钟输入 clk_in 和两个差分时钟输出 clk_p 和clk_n。 OBUFDS 原语:这是Xilinx提供的用于将单端时钟转换为差分时钟的原语。 .ODIV_RATIO("DIVIDE_BY_1"):这个参数用于设置时钟的分频比。在这个例子中,我们将其设置...
Divide by 3To implement a divide by 3, we need to count to 3 and so we will need two flip-flops to count states 2'b00, 2'b01, 2'b10. However since dividing factor is not equal to 2^n we need additional flip-flops to get a 50% duty-cycle. We can achieve this by shifting ...
moduleDiv20x(rst,clk,cet,cep,count,tc);// TITLE 'Divide-by-20 Counter with enables'// enable CEP is a clock enable only// enable CET is a clock enable and// enables the TC output// a counter using the Verilog languageparametersize=5;parameterlength=20;inputrst;// These inputs/output...
and modules are the basic structure that provides each simple function. Designers can take the "top-down" approach and divide complex functional modules into low-level modules. This step is usually done by the chief designer at the system level, while the lower-level modules are done by the ...
③以一个简单的2分频器为例，它的功能是将输入时钟信号的频率减半。假设输入时钟信号 clk_in 的频率是10MHz，周期为100ns。对于2分频器而言，就是每经过2个 clk_in 的周期，输出信号 clk_out 的状态改变一次。④实现2分频器的verilog代码可以这样写：module divide_by_two(input wire clk_in,output reg clk_...