module up_counter( output reg [7:0] out , // Output of the counter input wire enable , // enable for counter input wire clk , // clock Input input wire reset // reset Input ); //-------------Code Starts Here----
即便执行期间,循环次数代表的变量信号值发生了变化,repeat 执行次数也不会改变。 // repeat 循环语句reg[3:0] counter3 ;initialbegincounter3 ='b0;repeat(11)begin//重复11次#10; counter3 = counter3 +1'b1;endend forever 相当于 while(1) 。 通常,forever 循环是和时序控制结构配合使用的。 regclk ;...
reset_n) begin count <= 4’b0000; end else begin // update counter cou...
assign En_cnt = (u2_P2S_dout_vld & u2_P2S_din_rdy) | u1_P2S_dout_vld & u1_P2S_din_rdy; counter #(.CNT_NUM('d24), .ADD(1'b1)) u_counter( .clk (clk ), .rst_n (rst_n ), .En_cnt (En_cnt ), .cnt (cnt ), .cnt_last (cnt_last ) ); assign S2P_din = intv2_d...
Hi, Anyone please help me write a counter module in verilog in which count should be incremented in both positive edge and negaive edge clock...
20、3-11选择设计文件类型输入如下Verilog HDL语言的设计代码:module Countericik,rst_n,q, overflow);input icIk;inpu t rst_ n; out pu t reg 3:0 q;out put overflow;always (po sedge iclk or n egedge rst_n)beginif(rst_ n) q <= 4'hO;elsebegi nif(4'h9 = q) q <= 4'h0; else...
Verilog program for 8bit Up down counter Verilog program for 8bit Shift Register (SIPO,PISO,PIPO) Verilog program for Random Access Memory(RAM) Verilog program for Programmable clock Generator Verilog program for Finite State Machine (mealy) ...
这个问题 Dijkstra 已经解答过了，没错，就是你知道的 Dijkstra，Dijkstra 最短路径算法，荷兰语全名是...
*计数器; //**分频的counter * latch; *时序机; *RAM; //用synopsys的 *模块引用; *预编译; *与非门的verilog描述如下: //verilog使用和C语言相同的注释方法module nd02(a1,a2,zn);//一个verilog模块总是以module开始,以endmodule 结束,nd02是模块名,a1,a2,zn是模块的3个输入输出信号input a1,a2; ...
Verilog program for 8bit Up down counter Verilog program for 8bit Shift Register (SIPO,PISO,PIPO) Verilog program for Random Access Memory(RAM) Verilog program for Programmable clock Generator Verilog program for Finite State Machine (mealy) ...