select V.vend_id,count(prod_id) prod_id from Vendors V left join Products P on V.vend_id = P.vend_id group by V.vend_id order by vend_id; 今天13:07 英特尔_Software_engineer 嵌入式实战场景题目(一) 此部分不只包含面经内容,均是实战类型不必全文背诵,有思路即可后续收录于专栏:嵌入式最强...
在sql语句中,表示过滤条件是vend_id=1002或者vend_id=1003的是() 根据您输入的内容,为您匹配到题目: **在sql语句中,表示过滤条件是vend_id=1002或者vend_id=1003的是()** A. select * from products where vend_id=1002 or vend_id=1003; B. select * from products where vend_id in (1002,1003...
select vend_id, min(prod_price) as cheapest_item from Products group by vend_id order by cheapest_item; -- 一旦分组后的聚合字段,就不能用原字段名,得用别名 点赞 相关推荐 01-22 21:18 已编辑 圣芙蕾雅学园 C++ 牛客寒假营第一场题解 寒假营第一场题解Easy:A、B、D、GMid:E、H、J、M...
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下面语句中,表示过虑条件是vend_id=1002或vend_id=1003的是( ) A.select * from products where vend_id=1002 or vend_id=1003 B.select * from products where vend_id in (1002,1003); C.select * from products where vend_id not in (1004,1005); D.select * from products where vend_id=1002...
百度试题 结果1 题目补全语句: select vend_id,count(*) from products where prod_price>=10 group byvend_id ___ count(*)>=2; 相关知识点: 试题来源: 解析 答案: having 反馈 收藏
百度试题 结果1 题目补全语句:select vend_id,count(*) from products where prod_price>;=10 group by vend_id ___count(*)>;=2; 相关知识点: 试题来源: 解析 having 反馈 收藏
补全语句):selectvend_id,count(*)asnum_prodsfromproductsgroupby()。 补全语句):selectvend_id,count(*)asnum_prodsfromproductsgroupby()。 查看答案
下面语句中,表示过虑条件就是 vend_id=1002 或 vend_id=1003 的就是( )A.select * from products where vend_id=1002 or vend_id=1003B.select * from products where vend_id in (1002,1003);C.select * from products where vend_id not in (1004,1005);D.select * from p
select a.vend_id, ifnull(b.prod_id,0) from Vendors a left join (select vend_id, count(prod_id) as prod_id from Products group by vend_id) b on a.vend_id = b.vend_id order by a.vend_id;点赞 相关推荐 01-29 18:14 中南大学 Java 2025致普通年轻人的一封信 从普通院校毕业...