The Variant data type has a numeric storage size of 16 bytes and can contain data up to the range of a Decimal, or a character storage size of 22 bytes (plus string length), and can store any character text. The
'实例Dim name As StringDim age As IntegerDim height As DoubleDim birthday As Date 2.通用变量 声明 Variant 类型变量时，如果忽略数据类型，默认情况是 Variant 类型，因此下方两种方式是相同的。'语法Dim [变量名] As VariantDim [变量名]'实例Dim message As VariantDim message 3.数组 '语法'固定长度数...
Subtest()Dim vArray As Variant,dValue As Double Dim iRow As Integer,iCol As Integer vArray=Range("A1:C10000").Value2 'read all the values at once from the Excel cells,put into an array For iRow=LBound(vArray,1)ToUBound(vArray,1)For iCol=LBound(vArray,2)ToUBound(vArray,2)dValue=v...
Dim a As DoubleDim b As VariantDim i As Longa = 0b = 0For i = 1 To 100000a = a + CDec(0.00001)b = b + CDec(0.00001)NextMsgBox "双精度浮点型的结果是" & aMsgBox "小数型的结果是" & bEnd Sub 你的理解基本正确,这里先不用考虑变量是什么类型的,vb6中默认把常量0.00001当双精度数...
Function AverageArray(arr As Variant) As Double Dim sum As Double Dim count As Integer Dim i As Integer sum = 0 count = 0 For i = LBound(arr) To UBound(arr) sum = sum + arr(i) count = count + 1 Next i AverageArray = sum / count ...
变量可以声明为以下数据类型之一:Boolean、Byte、Integer、Long、Currency、Single、Double、Date、String(适用于可变长度的字符串)、String *length(适用于固定长度的字符串)、Object或Variant。 如果不指定数据类型,则默认分配Variant数据类型。 此外,你也可以使用Type语句创建用户定义的类型。
Dim Number As Double Number = 1505.5 / 2 ActiveCell = Str(Number) End Sub 数字十六进制转换 Visual Basic语言支持十六进制数。如果你有一个十进制数,但需要十六进制格式,可以转换它。为此,可以调用Hex函数。其语法是: Function Hex(ByVal Number As { Byte | Integer...
(8) Len函数对Variant类型变量的处理和字符串变量一样,Len函数返回变量所存储的实际字符数,如下面的代码: Dim vVar vVar=100 MsgBox Len(vVar) 结果为3。 (9) 由于VB本质上使用的是Unicode字符串(用两个字节的空间来存储一个字符),因此当相同的字符串变量传递给Len函数和LenB函数时会出现不同的返回值。例如...
DimMyDouble, MyString MyDouble =437.324' MyDouble is a Double.MyString =CStr(MyDouble)' MyString contains "437.324". CVar 函数示例 本示例使用CVar函数将表达式转换为Variant。 VB DimMyInt, MyVar MyInt =4534' MyInt is an Integer.MyVar = CVar(MyInt &000)' MyVar contains the string' 4534000. ...
Dim pointArrayAsVariantDim points()AsDoubleReDim points(0To11)AsDoublepoints(0) =-0.120448044187601points(1) =5.04048880567677E-02points(2) =0points(3) =-5.67327744361887E-02points(4) =5.38961357143793E-02points(5) =0points(6) =1.22193668016407E-02...