按钮代码：Private Sub CommandButton1_Click()Dim c1 As Long, c2 As Long, i As Longi = Me.ComboBox1.ValueIf i < 1 Then Exit SubsetSheetc1 = 11232'定义颜色1c2 = 823514'定义颜色2Dim R As Range, cell As RangeSet R = Range("A" & i).Resize(20, 10)'定义颜色区间For Each cell In ...
InputBox("请输入数字", "输入提示") If len(st) = 0 Then GoTo 100 End Sub gosub-return-跳过去,返回来 代码语言:javascript 代码运行次数:0 运行 AI代码解释 Sub test() Range("A1") = 100 GoSub 100 Range("A1") = 20 Exit Sub 100: Range("A1") = 50 Return End Sub 错误处理语句 On ...
可以实现，设置缩进为0或最大值250，任意选择缩进值选择框ComboBox设置缩进值。NO.5 代码 无缩进 With Range("B1").IndentLevel = 0End With 将B1单元格缩进值设置为0，也就是没有缩进。最大缩进 With Range("B1").IndentLevel = 250End With 将B1单元格缩进值设置为250，最大缩进值。如果你的应用出现报错...
假设我们要将Excel单元格中的最后三个字符替换为COMBOBOX的值,可以使用以下VBA代码实现: 代码语言:txt 复制 Sub ReplaceLastThreeCharsWithComboBoxValue() Dim ws As Worksheet Dim rng As Range Dim cell As Range Dim comboBoxValue As String ' 设置工作表和工作范围 Set ws = ThisWorkbook.Sheets(...
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1 首先在开发工具中打开VBA编辑器 2 在单元格区域当中输入一些内容作为例子 3 在VBA编辑器中插入模块 4 在模块当中输入如下代码，然后运行Private Sub UserForm_Initialize()'添加复合框下拉表Dim rng As RangeFor Each rng In Range(Cells(1, 1), Range("xfd1").End(xlToLeft))Me.ComboBox1.AddItem ...
第三种，定义了数组的元素是Range，这种情况目前我们碰到的比较少。为了演示，我们写了下面的代码：Sub RangeInArray() Dim arr() As Range Dim ws As Worksheet Set ws = Sheets("Sheet1") ReDim arr(1 To 15, 1 To 15) With ws .Activate For i = 1 To 15 For j = 1...
1 首先在开发工具中打开VBA编辑器 2 在单元格区域当中输入一些内容作为例子 3 在VBA编辑器中插入模块 4 在模块当中输入如下代码，然后运行Sub按钮1_Click()On Error Resume NextIf Not Sheets(1).ComboBox1 Is Nothing Then Sheets(1).ComboBox1.Clear'如果为组合框的数据则清除Dim cell As Range, ...
excel vba combobox duplicates unique 我陷入了这个问题,我必须将数据过滤到组合框中。列表应仅具有唯一的记录。下面是将记录填充到组合框中的代码: Private Sub UserForm_Activate() Dim myrng As Range Dim cl As Range Dim sh As Worksheet Set sh = Worksheets("Product_Master") Set myrng = sh.Range(...
Private Sub CommandButton1_Click()Application.ScreenUpdating = FalseSet s = ThisWorkbook.Worksheets(jl)ir = 2ic = s.Range("A1").End(xlToRight).ColumnDim x As Object, xi As IntegerReDim xVarr(0)xi = 0For Each x In Me.ControlsIf TypeName(x) = "TextBox" Or TypeName(x) = "ComboBox...