Const GCSAPPREGKEY As String ="DemoAddInInstallingItself" Const GCSAPPNAME As String ="DemoAddInInstallingItself" Public Function IsInstalled() As Boolean Dim oAddIn As AddIn On Error Resume Next If ThisWorkbook.IsAddin Then For Each oAddIn In Application.AddIns If LCase(oAddIn.FullName) <> L...
刚刚接触项目开发,遇到的一个问题,就写在这里。希望能够帮到像我一样的初学者。 在Java中String类型和Int类型的判断空值的方法是不同的。Int类型的变量是可以直接用null或者空字符串“”来进行判断的。例如:if(age != null &&age !=””){ …… }String类型则不可以这样判断。String类型应该用isNotEmpty ...
1.当判断的变量为数值型时(integer) 先判断是否为空在判是否为零 if (id != null && id != 0) { return false;//不为空}2.当判断的变量为字符串时时(String) Strings.isNotBlank(name){ return false;//不为空}3.当判断的变量为对象时(peopl ...
”EN在Excel内部打开VBA 以及在运行之前需要开启一下家开发人员的安全性 打开的页面可能是这样，不要慌 ...
Value '判断单元格不为空且不为空字符串 If Not (IsEmpty(str)) Then If str <> "" Then '第一次截取取第2个字符串,下表从0开始 'url: 'ABC Home Page - ABC.com,网址 split_result = Split(str, "url:")(1) '第二次截取取第1个字符串,下表从0开始 'ABC Home Page - ABC.com '网址 ...
VBA String functions Generally a more complete set ofVBA string functionsthan the once already available in VBA is needed. We borrowed the ideas from other languages, notably VB.NET. VBA Date functions Both built-inVBA Date functionsand custom functions and snippets included in the VBA Code Libr...
If MsgBox("你愿意安装'" & GCSAPPNAME & "' 作为加载项吗?",vbQuestion + vbYesNo, GCSAPPNAME) = vbYes Then If ActiveWorkbook Is Nothing Then AddEmptyBook Set oAddIn = Application.AddIns.Add(ThisWorkbook.FullName, False) oAddIn.Installed = True Remo...
If Not IsEmpty(myCell) Then myCell = Trim(myCell) End If Next myCell End Sub 此列表中最有用的宏之一。它将检查您的选择,然后从中删除所有多余的空格。 74. 从字符串中删除字符 Public Function removeFirstC(rng As String, cnt As Long) ...
End If MyName = dir ' 查找下一个目录。 Loop End Sub 以下过程利用递归可以查找目录和子目录下的所有文件。 Public Sub FindFile(mPath As String, Optional sFile As String = "") On Error Resume Next Dim s As String, sDir() As String ...
Private Sub Worksheet_SelectionChange(ByVal Target As Range) Dim RowNum, ListRows, ListStartRow, ListColumn As Integer Dim TheList As String Dim Repeated As Boolean If Target.Address <> "$D$5" Then Exit Sub With Range("k8:K38") ListRows = .Rows.Count ListStartRow = .Row ListColumn ...