Word VBA一句代码搞定——文档自动编号转文本 '选区编号转文本 selection.Range.ListFormat.ConvertNumbersToText '光标第一段编号转文本 selection.Paragraphs.First.Range.ListFormat.ConvertNumbersToText '全文编号转文本 activedocument.Range.ListFormat
Sub ConvertTextToNumber_ErrorHandling() On Error GoTo ErrHandler Dim rng As Range Set rng = Selection ' 确保选择的是单元格范围 If Not rng Is Nothing Then rng.TextToColumns Destination:=rng, DataType:=xlFixedWidth, FieldInfo:=Array(0, 1) Else MsgBox "请选择需要转换的单元格区域。", vbExcla...
Here is a revision to your code that steps through the paragraphs backwards and converts the number to text. For counter = ActiveDocument.Paragraphs.Count To 1 Step -1 If Len(Paragraphs(counter).Range.ListFormat.ListString) > 0 Then Paragraphs(counter).Range.ListFormat.ConvertNumbersTo...
Convert String to Decimal MsgBox CDbl("9.1819") MsgBox CDec("13.57") + CDec("13.4") Convert String to Currency ange("A1").Value = CCur("18.5") REF: https://www.automateexcel.com/vba/convert-text-string-to-number/ VBE2019,Rubberduck:Excel VBA 的插件。
Sub ConvertTextToNumbers() 'Worksheets("Sheet4").Range("A1").NumberFormat= "General" '如...
Sub ConvertTextToNumber() Dim ws As Worksheet Dim rng As Range Dim cell As Range ' 循环遍历所有工作表 For Each ws In ThisWorkbook.Worksheets ' 设置要转换的范围,这里假设要转换的范围是A1到Z100 Set rng = ws.Range("A1:Z100") ' 循环遍历范围内的每个单元格 For Each cell In rng ' 检查单...
Excel VBA Convert Text String to Number 文章分类Python后端开发 Convert String to Integer MsgBox CInt("7.55") MsgBox CLng("13.5") Debug.Print "13.5" + "13.5" Sub Using_Variables() Dim valueOne As String valueOne = 5 MsgBox CLng(valueOne) + CLng(valueOne)...
问在Excel VBA中将以文本形式存储的数字转换为数字的最简单方法ENSubConvertTextNumberToNumber()For Each...
2. Excel Convert Number to Date or Date to String Choose the cell that has data & use the Excel date format conversion as explained below. Select Excel cell that has Date. Right Click & choose “Format Cells” (short cut –‘CTRL + 1’). ...
Converts a number from 100-999 into text * '*** Function GetHundreds(ByVal MyNumber) Dim Result As String If Val(MyNumber) = 0 Then Exit Function MyNumber = Right("000" & MyNumber, 3) ' Convert the hundreds place. If Mid(MyNumber, 1, 1) <> "0" Then Result = GetDigit(Mid...