SubAssignRangeToArrayDemoBad1()'THIS MACRO WILL GENERATE AN ERRORDimMyArray()AsVariant'unallocated arrayMyArray=ActiveSheet.Range("A1:G311")'Creates a Type mismatch errorEndSub The macro above will generate an error because it hasActiveSheetin front of the range. However, the following, very si...
For i = LBound(arr2) To UBound(arr2) Debug.Print arr2(i) Next i 以下是完整的代码示例: vba Sub AssignArrayValues() Dim arr1() As Integer arr1 = Array(1, 2, 3, 4, 5) Dim arr2() As Integer ReDim arr2(LBound(arr1) To UBound(arr1)) Dim i As Integer For i = LBound...
' start indexing array elements at 1 Option Base 1 Sub FunCities() 'declare the array Dim cities(1 to 5) As String 'assign the values to array elements cities(1) = "Las Vegas" cities(2) = "Orlando" cities(3) = "Atlantic City" cities(4) = "New York" cities(5) = "San Francis...
Sub AssignArrayToRange() Dim arr(1 To 3, 1 To 3) As Integer Dim rng As Range '给数组赋值 arr(1, 1) = 1 arr(1, 2) = 2 arr(1, 3) = 3 arr(2, 1) = 4 arr(2, 2) = 5 arr(2, 3) = 6 arr(3, 1) = 7 arr(3, 2) = 8 arr(3, 3) = 9 '将数组赋值给单元格区...
MyVar="45 Help"' Assign value. MyCheck = IsNumeric(MyVar) ' ReturnsFalse. Join 函数 返回通过连接数组中包含的大量子字符串创建的字符串。 语法 联接(sourcearray, [定界符]) Join 函数语法包含以下命名参数: 语法 sourcearray 必需。 一维度组,包含要连接的子字符串。
Sub Array_Example() Dim Student(1 To 5) As String Dim K As Integer For K = 1 To 5 Next K End Sub To assign values to the array variable, we need not follow the previous way of showing Student(1) and Student(2) for numbers position supply loops variable "k." Code: Sub Array_...
SubAssignValueToTableFromArray()'赋值给数组 Dim myArray As Variant myArray=Range("A20:D20")'赋数组中的值给表 ActiveSheet.ListObjects("myTable").ListRows(2).Range.Value=myArray End Sub 引用表的某部分 可以像标准的单元格对象一样引用表。
问通过循环将一个动态数组的值赋值给另一个具有更改的数组(VBA)ENfor i in ${a[*]} # 定义fo...
' start indexing array elements at 1 从1开始给数组成员编号 Option Base 1 Sub FavoriteCities() 'now declare the array Dim cities(6) As String 'assign the values to array elements cities(1) = "Baltimore" cities(2) = "Atlanta" cities(3) = "Boston" ...
The table_array, however, needs to be presented ina format that VBA can handle.Here we’ve used Range(“A1:B51”), which selects the cells in A1:B51. It’s important to remember that you can’t just type “A1:B51”, as VBA won’t recognize the range ...