nickels and ( ) dimes. A. 5B. 15C. 20D. 25相关知识点: 试题来源: 解析 B The value of 10 nickels = the value of 5 dimes; the value of 20 nickels and 10 dimes = the value of 10 nickels and 15 dimes. 20个镍币和 10 个一角硬币的价值与 10 个镍币和多少个硬币的价值相同 ( )...
nickels and 5 dimes is the same as the total value of quarters. A.3 B.4 C.5 D.6相关知识点: 试题来源: 解析 A 5个5美分和5个5角的价值与多少个25美分相等? 5个5美分:5×5=25美分, 5个5角:5×10=50美分, 总共25+50=75美分, 75÷25=3个与3个25美分相等. 故选A.结果...
1 penny +1 nickel +1 dime=16¢.It takes 15 of these 16¢ groups to be worth ＄2.40. The value of the 15 nickels is 75¢. 若同等数量的面值为1美分,5美分,10美分的硬币的总钱数是2.4美元,则面值为5美分的硬币总钱数是( ). A.45美分B.50美分C.60美分D.75美分 2.4美元=240美分,240...
dimes and n nickels equals the value of (n−d) quarters, then d:n=( ). A. 4:7B. 7:4C. 1:2D. 2:1相关知识点: 试题来源: 解析 A We're told that 10d+5n=25(n−d), so 10d+5n=25n−25d, from which 35d=20n, Dividing by 35n, d:n=20:35=4:7. d个面值为十美分与...
【题目】T he total value of 5 nickels and 5 dimes is the same as the total value of __ qu
nickels. If I choose a coin at random, the probability that it will be a nickel is ( ). A.12 B.23 C.43 D.47相关知识点: 试题来源: 解析 D 我有一角硬币和五分镍币总值1美元, 我正好有8个镍币,如果我随机选择一枚硬币, 它是一枚五分硬币的概率是? 8个镍币总值:8×5=40(分)=4角, 所以...
The value of one of each coin is (1+5+10)￠=16￠, Since 2.40÷16￠=15, there are 15 of each coin, The value of 15 nickels is 15×5￠=75￠. 相同数量的一分硬币,五分硬币,十分硬币总共价值2.40美元,那么五分硬币价值多少钱( ). A.15￠ B.50￠ C.75￠ D.95￠ 每样一个的话,价值...
If the total value of an equal number of pennies, nickels, and dimes is ＄2.40, how many coins are there altogether( ). A. 60B. 45C. 30D. 15相关知识点: 试题来源: 解析 B 1 penny +1 nickel +1 dime =16￠. Since 15 of these 16￠groups are worth ＄2.40 , there are 15 of ...
dimes . Nickels make up what fraction of the total value of Cy’s 150 coins?( ) A.1/2 B.1/3 C.1/4 D.1/5相关知识点: 试题来源: 解析 D 赛伊有50个五分硬币和100个一角硬币.五分硬币占这150个硬币总价值的几分之一? 50×5=250(分),求出五分硬币的价值. 1角=10分, 100×10=1000...
使用美元硬币(面值有一分钱,五分钱,十分钱,25分钱) the maximum value:最大值;change:找回的零钱;coins:硬币;pennies:一分钱;nickels:五分钱;dimes:十分钱,一毛钱;quarters:25分钱,两毛五;a one-dollar bill:一个一美元的账单; 3 quarters,4 dimes,0 nickels,4 pennies,总共1.19美元,所以选C....