1 penny +1 nickel +1 dime=16¢.It takes 15 of these 16¢ groups to be worth ＄2.40. The value of the 15 nickels is 75¢. 若同等数量的面值为1美分,5美分,10美分的硬币的总钱数是2.4美元,则面值为5美分的硬币总钱数是( ). A.45美分B.50美分C.60美分D.75美分 2.4美元=240美分,240...
The total value of five pennies, five nickels, and five dimes is( ). A. 15￠ B. 60￠ C. 70￠ D. 80￠相关知识点: 试题来源: 解析反馈 收藏
The value of one of each coin is (1+5+10)￠=16￠, Since 2.40÷16￠=15, there are 15 of each coin, The value of 15 nickels is 15×5￠=75￠. 相同数量的一分硬币,五分硬币,十分硬币总共价值2.40美元,那么五分硬币价值多少钱( ). A.15￠ B.50￠ C.75￠ D.95￠ 每样一个的话,价值...
If the total value of my nickels equals the total value of 75 pennies,I must have exactly( ) nickels. A. 5 B. 15 C. 25 D. 75. 相关知识点: 试题来源: 解析 B. 题目的意思是如果我的全部五分镍币的价值是75美分,那么我有多少个5分镍币? 75÷5=15(个),所以答案选择B.. ...
If the total value of an equal number of pennies, nickels, and dimes is ＄2.40, how many coins are there altogether( ). A. 60B. 45C. 30D. 15相关知识点: 试题来源: 解析 B 1 penny +1 nickel +1 dime =16￠. Since 15 of these 16￠groups are worth ＄2.40 , there are 15 of ...
使用美元硬币(面值有一分钱,五分钱,十分钱,25分钱) the maximum value:最大值;change:找回的零钱;coins:硬币;pennies:一分钱;nickels:五分钱;dimes:十分钱,一毛钱;quarters:25分钱,两毛五;a one-dollar bill:一个一美元的账单; 3 quarters,4 dimes,0 nickels,4 pennies,总共1.19美元,所以选C....
Pat has 10 pennies and 10 nickels, The value of these coins is( ). A: 20 ￠ B: 50 ￠ C: 60 ￠ D: 81.10 相关知识点: 试题来源: 解析 C10 pennies=10 ￠ And 10 nickels=50 ￠, The value is 60 ￠,潘特有一美分和五美分的硬币各10个,这些硬币的总价值是( ).A.20美分 B.50美分 ...
解析 D50 pennies +10 nickels +5 dimes=50￠+50￠+50￠=$1.50.哪个和50便士+10镍币+5角硬币的价值相同( ).A. 2个25美分 B.4个25美分 C.5个25美分 D.6个25美分50便士+10个镍币+5个一角硬币=50美分+50美分+50美分=1.50美元.故选D.
解析 C 7×25￠+6×10￠+5×5￠+4×1￠=1.75+0.60+0.25+0.04=2.64. 7个25美分,6个10美分,5个5美分和4个1美分的总价值是多少( ). A.22美分B.1.64美元C.2.64美元D.3.64美元 7×25￠+6×10￠+5×5￠+4×1￠=1.75+0.60+0.25+0.04=2.64. 故选C....
anickels cost 7.7 cents to make , 2.7cents over faces value,as opposed to 0.26 cents over face value to make a penny.Since the penny costs 0.26 more than face value to make , the Mint can make 5 pennies and still lose less money than making 1 nickel 镀镍费用7.7分做, 2.7cents结束面值...