必须和新进来的右括号进行匹配,负责就是非法字符串## 这是一个比较巧妙的方法,先在栈底部加入一个元素,以解决空字符串的问题classSolution(object):defisValid(self,s):""":type s: str 字符串类型:rtype: bool 返回布尔型"""stack=['A']## 栈底加入了 A 字符m={')':'(',']':'[','...
Given a string containing just the characters'(',')','{','}','['and']', determine if the input string is valid. The brackets must close in the correct order,"()"and"()[]{}"are all valid but"(]"and"([)]"are not. 原题链接:https://oj.leetcode.com/problems/valid-parentheses...
小刀初试 [LeetCode] Valid Parentheses 解题报告 Given a string containing just the characters'(',')','{','}','['and']', determine if the input string is valid. The brackets must close in the correct order,"()"and"()[]{}"are all valid but"(]"and"([)]"are not. » Solve th...
参考:https://leetcode.com/problems/valid-parentheses/discuss/9252/2ms-C%2B%2B-sloution
LeetCode Valid Parentheses 有效括号 1 class Solution { 2 public: 3 void push(char c){ //插入结点 4 struct node *n=new struct node; 5 n->nex=0; 6 n->ch=c; 7 n->pre=last; 8 last->nex=n; 9 last=last->nex; 10 } 11 bool jud(char c){ //判断...
【leetcode】20-ValidParentheses problem Valid Parentheses code class Solution { public: bool isValid(string s) { stack<char> paren; for(const auto& c : s) { switch(c) { case '(': case '{': case '[': paren.push(c); break;...
链接:https://leetcode-cn.com/problems/valid-parentheses 解题思路 1. 利用计数的方法统计是否左右括号的数量是否匹配 设定int型变量 left、right,统计左右括号的数量,判断其是否相等(方法很笨) 另外一种是设定一个int变量称之为left,初始值为0。 遍历整个字符串,出现一个左括号则变量+1,出现一个右括号则变量...
20 Valid Parentheses 有效的括号 Description: Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same type of brackets. ...
LeetCode_20: Valid Parentheses 引言 题目链接:https://leetcode.com/problems/valid-parentheses/description/ #题目大意 输入一个由各种括号组成的字符串,按照如下规则判断字符串是否有效 条件: 开括号必须由相同类型的括号来关闭,即 '(' 由 ')' 关闭、'[' 由 ']' 关闭,'{' 由 '}' 关闭....
s仅由括号'()[]{}'组成 预览评论 💡 讨论区规则 排序:最热 1 2 3 4 5 6 classSolution{ public: boolisValid(strings) { } }; Case 1Case 2Case 3Case 4 s = "()" 9 1 2 3 4 › "()" "()[]{}" "(]" "([])" Source...