For two anagrams, once they are sorted in a fixed order, they will become the same. This code is much shorter (this idea can be done in just 1 line using Python ashere). However, it takes much longer time --- 76 ms in C++. 1classSolution {2public:3boolisAnagram(strings,stringt)...
也可以排序后逐个比对,复杂度O(nlogn)。 第一种方法: AC代码 AC代码 第二种方法: AC代码 AC代码 python3 AC代码 AC代码 AC代码 AC代码
Given two strings s and t, return true if t is an anagram of s, and false otherwise.An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using al…
解法二:哈希表,判断两个字符串相同字母的个数是否相等 1classSolution {2public:3boolisAnagram(strings,stringt) {4intlen_s = s.length(), len_t = t.length(), i, ns[26] = {0};5//vector<int> ns(26, 0);67for(i =0; i < len_s; i++)8ns[s[i] -'a']++;9for(i =0; i ...
1. 2. Note: You may assume the string contains only lowercase alphabets. Follow up: What if the inputs contain unicode characters? How would you adapt your solution to such case? 题解: hash表即可。 classSolution{ public: boolisAnagram(strings,stringt) { ...
链接:https://leetcode.com/problems/valid-anagram/ 242-valid-anagram.JPG 这题的做法有两种, 第一种:首先将字符串转换成list,然后进行排序。判断两个list是否相同。O(n)=nlog(n) .(快排) 第二种: 1.建立一个存放26个字母的list,并将它们值初始化为0; ...
242. 有效的字母异位词 Valid Anagram LeetCodeCN 第242题链接 第一种方法:对两个字符串排序后对比 classSolution:defisAnagram(self,s:str,t:str)->bool:returnsorted(s)==sorted(t) 第二种方法:用哈希表对字符串内每个字符计数,最后比对哈希表,这里用dict实现 ...
LeetCode 242. Valid Anagram 简介:给定两个字符串 s 和 t ,编写一个函数来判断 t 是否是 s 的一个字母异位词。 Description Given two strings s and t , write a function to determine if t is an anagram of s. Example 1: Input: s = "anagram", t = "nagaram"...
【摘要】 这是一道关于字符串排序比较的LeetCode题目,希望对您有所帮助。 题目概述: Given two strings s and t, write a function to determine if t is an anagram of s. For example, s = "anagram", t = "nagaram", return true.
Can you solve this real interview question? Valid Anagram - Given two strings s and t, return true if t is an anagram of s, and false otherwise. Example 1: Input: s = "anagram", t = "nagaram" Output: true Example 2: Input: s = "rat", t = "car" O