结果1 题目 Using the Quadratic Formula, which of the following is the solution to the quadratic equation 3x^2+5x-12=0? ( ) A. x=-3, x=43 B. x=3, x=43 C. x=3, x=-43 D. x=-3, x=-43 相关知识点: 试题来源: 解析 A 反馈 收藏 ...
x^2+6x+9=0: 解:x=-3 x^2+7x+10=0: 解:x=-2, x=-5 x^2+4x-21=0: 解:x=-7, x=3反馈 收藏
Equation: 16y^2 - 8y - 3 = 0 Equation: x^2 = 15 + 2x Show answer Show answer Show answer Equation: q^2 - 7.5q + 25 = -q^2 - 7.5q Show answer Show all answers Solve by Using the Quadratic Equation Lesson Brush up on your knowledge of the techniques needed to solve problems ...
Using decimal numbers will not require us to use the Quadratic Formula any differently. In this case, the equation is already in the correct format. Using “ax2 + bx + c = 0,” we must now determine a, b, and c. Now we can substitute into the Quadratic Formula:...
题目#2: Solve the equation below using the Quadratic Formula. Select the answer(s) below.★x^2+2x-15=02.74-2.744.74-4.74口5-53#3 相关知识点: 试题来源: 解析 x^2+2x-15=0 x=-2±√(2^2-4(1+-15)) , =-2±√(4+60) 28 =-14=3 反馈 收藏 ...
Viète's formulas are important elements of elementary mathematics, it reveals the relationship between roots and coefficients of a quadratic equation. Using the theory of polynomials to promote it to a $ n in the equation, and its simple application. Because of Viète's formulas reveal a relatio...
Solve the equation using the quadratic formula. {eq}4x^2 + 10x + 3 = 0 {/eq} Quadratic Formula Given a quadratic equation of the form {eq}ax^2+bx+c=0, {/eq} one can solve for the unknown variable {eq}x {/eq} by using the quadratic formula: $$x = \frac{...
Move all the expressions to the left side of the equation.( 3x^2+2x-4=0)Use the quadratic formula to find the solutions.( (-b± √(b^2-4(ac)))/(2a))Substitute the values ( a=3), ( b=2), and ( c=-4) into the quadratic formula and solve for ( x).( (-2± √(2^2...
Move all terms to the left side of the equation and simplify.( 4x^2+4x-48=0)Use the quadratic formula to find the solutions.( (-b± √(b^2-4(ac)))/(2a))Substitute the values ( a=4), ( b=4), and ( c=-48) into the quadratic formula and solve for ( x).( (-4± ...
Solve each equation using the quadratic formula. -4x^2+2x+3=0 相关知识点: 试题来源: 解析 x= (\ 1± √ (13))4 -4x^2+2x+3=0, so a=-4, b=2, c=3.x= (-(2)±√ (2^2-4(-4)(3)))(2(-4))= (-2± √ (52))(-8)= (\ 2± √ 4√ (13))8= (\ 2± 2√ (...