a假设S为已求得最短路径的终点的集合,则可证明:下一条最短路径(设其终点用户为x)或者是路线(i,x),或者是中间只经过S中的顶点而最后到达用户X的路径。这可用反证法来证明。假设此路径上有一个顶点不在s中,则说明存在一条终点不在s而长度比此路径短的路径。 正在翻译,请等待... ...
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