classMain{staticvoidmain(String[]args)throws IOException,MalformedURLException{String path1="d:\\t.txt",path2="file:/d:/t.txt";Main main=newMain();main.readByFr(path1);main.readByUrl(path2);}// 通过FileInputStream的写法voidreadByFr(String path)throws IOException{FileReader fr=newFileRead...
Describe the bug "Internal server error: URI malformed" when using a percent sign in URL Reproduction https://github.com/hichemfantar/vite-bug-repro Steps to reproduce create a file with % in name import it System Info System: OS: Linux 5.15 Ubuntu 20.04.6 LTS (Focal Fossa) CPU: (12)...
fr.close(); } } // 通过URL的写法 void readByURL(String path) throws MalformedURLException, IOException{ URL url = new URL(path); InputStreamReader reader = new InputStreamReader(url.openStream()); try{ int buf; while (-1 != buf){ buf = reader.read(); System.out.print((char)buf...
Unhandled Error URIError: URI malformed at decodeURIComponent (<anonymous>) at _urlToPath ([REDACTED]\app.asar\app\protocol_filter.js:19:19) at Function.<anonymous> ([REDACTED]\app.asar\app\protocol_filter.js:30:35) Logs: https://debuglogs.org/36bf80ca3ceb84dacbe3aaadc5ed2e03c46c0...
fr.close(); } }//通过URL的写法voidreadByURL(String path) throws MalformedURLException, IOException{ URL url=newURL(path); InputStreamReader reader=newInputStreamReader(url.openStream());try{intbuf;while(-1!=buf){ buf=reader.read(); ...
} catch (MalformedURLException e) { e.printStackTrace(); } try { HttpURLConnection conn = (HttpURLConnection) myFileUrl.openConnection(); conn.setConnectTimeout(0); conn.setDoInput(true); conn.connect(); InputStream is = conn.getInputStream(); ...
fr.close(); } } // 通过URL的写法 void readByURL(String path) throws MalformedURLException, IOException{ URL url = new URL(path); InputStreamReader reader = new InputStreamReader(url.openStream()); try{ int buf; while (-1 != buf){ ...
URIError:URI malformed是什么意思?领礼包时总出这个提示,怎么解决啊 分享5赞 苏美尔吧 酷酷游戏 鼓捣半天,古代苏美人《城表》位列第五的城市是:凯什(kesz3)3.阿拉玛(拉尔萨,但阿日一位学者在论文中将其定义为:阿达布,但未给出理由与说明)4.乌鲁克4a.阿达布(这个4a到底什么意思,不明确,但CDLI上原文如此。
URL类有多个构造函数。其中最简单的是URL(String url),它有一个String类型的参数。如果某个URL没有包含协议处理程序或该URL的协议是未知的,其它的构造函数会产生一个java.net.MalformedURLException。 下面的代码片断演示了使用URL(String url)建立一个URL对象,该对象封装了一个简单的URL组件和http协议处理程序。
}catch(Exception e) {// ignore malformed uri, then attempt to extract resource ID.}if(uri ==null) { uri = getResourceDrawableUri(getThemedContext(), source); } }if(uri != mUri) { markUpdated(); } mUri = uri; } 开发者ID:qq565999484,项目名称:RNLearn_Project1,代码行数:25,代码来源...