}$sets=$bindings=[];$updateSql= "UPDATE `" . config('database.connections.mysql.prefix').$table. "` SET ";$data=array_keys($values[0]);$data=array_diff($data,[$index]);foreach($dataas$field) {$setSql= '`' .$field. '` = (CASE ';foreach($valuesas$key=>$val) {if($ra...
在php项目中,通过medoo库简单连接到了mysql.由于需要批量更新配置操作,使用了insert into ... on duplicate key update语句,该语句无法却通过pdo的语法检测,php代码如下: $medoo = new Medoo($dbcfg); $sql = "INSERT INTO `t_config` (`name`,`value`) VALUES ('WEB_SITE_TITLE','11dd11'),('WEB_...
48}4950if(is_array($options['where']) &&isset($options['where'][$pk])){51$pkValue=$options['where'][$pk];52}53if(false===$this->_before_update($data,$options)) {54returnfalse;55}56$result=$this->db->update($data,$options);57if(false!==$result&&is_numeric($result)) {58i...
我在cakephp中使用了ajax表单提交 echo $ajax->submit('Submit', array('url'=> array('controller'=>'projects', 'action'=>'add_comment'), 'update' => 'feedback_'.$value['contest_submission']['id'])); 提交表单后,更新的div内容变为null 浏览2提问于2011-09-12得票数 0 回答已采纳 2回答...
}if(is_array($options['where']) &&isset($options['where'][$pk])){$pkValue=$options['where'][$pk]; }if(false===$this->_before_update($data,$options)) {returnfalse; }$result=$this->db->update($data,$options);if(false!==$result&& is_numeric($result)) {if(isset($pkValue)...
到这里,已经完成一条mysql语句更新多条记录了。 但是要在业务中运用,需要结合服务端语言,这里以php为例,构造这条mysql语句: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 $display_order=array(1=>4,2=>1,3=>2,4=>3,5=>9,6=>5,7=>8,8=>9);$ids=implode(',',array_keys($display_order...
48}4950if(is_array($options['where']) &&isset($options['where'][$pk])){51$pkValue=$options['where'][$pk];52}53if(false===$this->_before_update($data,$options)) {54returnfalse;55}56$result=$this->db->update($data,$options);57if(false!==$result&&is_numeric($result)) {58...
print_r(array_values($Approval)); echo ""; foreach($Approval as $field=>$data) { echo "ID: ".$data[ID]." Approve: ".$data[accept].""; mysql_connect("$Server","$DB","$Password"); mysql_select_db("$DB"); $updatestring...
My workaround for now is to show the field as a regular text field in the update view in order to show the stored value, but I would like to use the ajax search in the update view too. PHP VERSION: PHP 8.1.12-1ubuntu4.3 (cli) (built: Aug 17 2023 17:37:48) (NTS) Copyright ...
but i entered all the databases information into an array ($rows).. so there for i tested already by doing: echo $rows[0][0]; and i get the first customers name on the browser so why cant i get this to work? am i formatting it wrong or is there a different way to do this?