Unknown column ‘XX.ID;‘ in ‘group statement‘ 出现该提示可能是SQL中有中文字符,通常为结尾的; 例:select a.approvalstatus,count(1) sum from lzcardapp a where a.approvalstatus is not null GROUP BY a.approvalstatus; -- 最后的分号为中文字符,所以报错。
针对你提供的错误信息 errmsg = "error:unknown column 'mnltype' in 'group statement'",我们可以按照以下步骤进行解析和解决: 解析错误消息内容: 错误消息表明在执行SQL查询时,数据库在group statement中找不到名为mnltype的列。 确认'mnltype'列在数据库表中的存在性: 需要检查你的数据库表中是否确实存在名...
1、错误描写叙述 1queries executed,0success,1errors,0warnings查询:selectcount(t.id),t.`createUserId`fromt_acs_ints twheret.idnotin(SELECTt1.ionIdFROMt_acs_cont t1,t_ac...错误代码:1054Unknowncolumn't.createUsrId'in'group statement'运行耗时 :0sec 传送时间 :0sec 总耗时 :0sec 1. 2....
错误代码: 1054 Unknown column 't.createUsrId' in 'group statement' 执行耗时 : 0 sec 传送时间 : 0 sec 总耗时 : 0 sec 2、错误原因 在SQL语句分组时,由于粗心导致字段少写一个字母,导致该字段无法识别(即在表中不存在),致使报错;数据库表的字段名为createUserId,而在group by后面写成了createUsrId ...
Unknown column 't.createUsrId' in 'group statement' 运行耗时 : 0 sec 传送时间 : 0 sec 总耗时 : 0 sec 2、错误原因 在SQL语句分组时。因为粗心导致字段少写一个字母,导致该字段无法识别(即在表中不存在),致使报错;数据库表的字段名为createUserId,而在group by后面写成了createUsrId ...
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'craft_elements.id' in 'group statement' The SQL being executed was: SELECT `elements`.`id`, `elements_sites`.`siteId`, COUNT(*) as count FROM (SELECT `elements`.`id` AS `elementsId`, `elements_sites`.`id` AS `elementsSitesId...
First in scopeSearchRestricted() function and secondly in makeGroupBy() functions I found a solution that we need to replace code from line 209 to 2016 with below code $prefix = Config::get("database.connections.$driver.prefix"); foreach ($this->getColumns() as $column => $relevance) ...
I’ve tried to make Martin the arbiter of his own food choices. I created a chart with four columns labeledfoods I never eat(this column comprised only gluten and his food allergies),foods I try to avoid,foods I eat sparingly(“Mommy, what’s ‘sparingly’?”), andfoods I eat as muc...