return str(int(code.upper(),16)) if __name__ =="__mian__": for i in range(10,500,35): code = activation_code(i) id_hex = code.split('L')[0] id = get_id(id_hex) print (code,id) if __name__=="__main__": for i in range(10,200,35): code = activation_code(i...
Code README Apache-2.0 license ulid Universally Unique Lexicographically Sortable IdentifierinPython 3. Status This project is actively maintained. Installation To install ulid frompip: $ pip install ulid-py To install ulid from source: $ git clone git@github.com:ahawker/ulid.git $cdulid&&python...
AI代码解释 In[30]:importpandasaspd...:...:# 创建示例 DataFrame...:data={'Name':['Alice','Bob','Charlie','Alice','Charlie'],...:'Age':[25,30,35,25,35],...:'City':['New York','Paris','London','New York','Sydney']}...:df=pd.DataFrame(data)In[59]:df Out[59]:Name...
下列代码第2次执行时,插入记录提示:IntegrityError: UNIQUE constraint failed: table_juzicode._id #juzicode.com/vx:桔子code importsqlite3 #检查表是否存在,存在返回True defcheck_table_exsist(cursor,table_name): sql ='''SELECT tbl_name FROM sqlite_master WHERE type = 'table' ''' cursor.execute(s...
代码(Python3) class Solution: def uniquePathsWithObstacles(self, obstacleGrid: List[List[int]]) -> int: m, n = len(obstacleGrid), len(obstacleGrid[0]) # dp[i][j] 表示从 (0, 0) 到 (i - 1, j - 1) 的不同路径数, # 初始化均为 0 dp: List[List[int]] = [[0] * (n ...
现在总结一下unique,unique的作用是“去掉”容器中相邻元素的重复元素(不一定要求数组有序),它会把重复的元素添加到容器末尾(所以数组大小并没有改变),而返回值是去重之后的尾地址,下面举个例子。 由于返回的是容器末尾,所以如果想得到去重后的size,需要减去初始地址,lower_bound是得到地址,稍微不同。 如: ...
[LeetCode]题解(python):062-Unique Paths 题目来源: https://leetcode.com/problems/unique-paths/ 题意分析: 给定两个整型m,n。判断从一个m×n的矩阵里面,从(0,0)走到(m-1,n-1)一共有多少种法(只能往下和往右走)。 题目思路: 这可以看成一个组合问题。从(0,0)到(m-1,n-1)一共要走m - ...
Python Exercises Home ↩ Previous:Write a Python script that takes input from the user and displays that input back in upper and lower cases. Next:Write a Python function to create the HTML string with tags around the word(s). Python Code Editor: ...
2019-12-13 22:36 −Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0... Zhentiw 0 175 利用Python进行数据分析-Pandas(第五部分-数据规整:聚合、合并和重塑) 2019...
标签: Java Python 算法 收藏 LeetCode 387: 字符串中的第一个唯一字符 First Unique Character in a String 题目: 给定一个字符串,找到它的第一个不重复的字符,并返回它的索引。如果不存在,则返回 -1。 Given a string, find the first non-repeating character in it and return it’s index. If ...