Every integer representedinthe 2D-array will be between1and N,whereNisthe size of the input array. 题解:我是用并查集解的。对于每一条边的两个结点,如果他们的爸爸不是同一个爸爸,那么就 unoin 这两个结点,如果他们两个的爸爸是同一个爸爸,就说明这条边多余了,直接返回这条边就行
classSolution {//union findclassQuickUnion {//with arrayHashMap<Integer, Integer> map =newHashMap<>();//id, parentHashMap<Integer, Integer> sz =newHashMap<>();//id sizeintcount;//how many componentsQuickUnion(int[] nums){ count= 1;for(inti = 0; i<nums.length;i++) { map.put(...
You are given a string s, and an array of pairs of indices in the string pairs where pairs[i] = [a, b] indicates 2 indices(0-indexed) of the string. You can swap the characters at any pair of indices in the given pairs any number of times. Return the lexicographically smallest str...
publicclassUnionFind01implementsUF{//我们第一种实现,Union-Find本质就是一个数组privateint[]id;//有参构造:指定并查集中元素的个数publicUnionFind01(int size){id=newint[size];//初始化, 每一个id[i]指向自己, 没有合并的元素for(int i=0;i<id.length;i++)id[i]=i;}@OverridepublicintgetSize(...
Union Find # 灵活使用并查集的思想,熟练掌握并查集的 模板,模板中有两种并查集的实现方式,一种是路径压缩 + 秩优化的版本,另外一种是计算每个集合中元素的个数 + 最大集合元素个数的版本,这两种版本都有各自使用的地方。能使用第一类并查集模板的题目有:第 128 题
All my leet code solutions in Java javatreelinked-listgrapharraycompetitive-programmingdata-structuresdfsbinary-search-treedynamic-programmingbfsgreedy-algorithmsbinary-searchunion-find UpdatedAug 9, 2021 Java graph based image segmentation for better 2D screw hole recognition ...
[435. 无重叠区间](https://leetcode-cn.com/problems/non-overlapping-intervals/) 一维 方法一、模拟 方法二、并查集 [1569. 将子数组重新排序得到同一个二叉查找树的方案数](https://leetcode.cn/problems/number-of-ways-to-reorder-array-to-get-same-bst/) [LCS 03. 主题空间](https://leetcode.cn...
(https://leetcode.cn/problems/gcd-sort-of-an-array/) 2429 // // 数组标记/区间合并相关 // - 经典模型是一维区间覆盖染色,通过倒序+并查集解决 // - 顺带补充下二维的情况(非并查集):LC2718 https://leetcode.cn/problems/sum-of-matrix-after-queries/ // https://codeforces.com/...
第一个是Leetcode 803. Bricks Falling When Hit. We have a grid of 1s and 0s; the 1s in a cell represent bricks. A brick will not drop if and only if it is directly connected to the top of the grid, or at least one of its (4-way) adjacent bricks will not drop. ...
【typescript类型体操-04】实现 First of Array 的四种解题思路( extends、indexed、union、infer) 1.3万 38 1:17:24 App TS 体操 TwoSum|程序员技术二面模拟【Anthony Fu x Herrington】 702 -- 28:36 App TypeScript第二期: 『extends』 3922 10 8:53 App 【typescript类型体操-05】实现 Length Of ...