This approach is of great accuracy and efficiency for large text datasets. This study thereby identified the centurial-scale topics related to lakes using large literature datasets covering >130,000 studies. The results showed that the topics became more and more abundant but were concentrated stably...
By default, Minitab's Test for Equal Variances command displays results for Levene's method and the multiple comparisons method. For most continuous distributions, both methods give you a type I error rate that is close to your specified significance level (also known as a...
README_EN.md Add Lingzhi 72B results (haonan-li#80) Aug 22, 2024 Repository files navigation README CMMLU---中文多任务语言理解评估简体中文 | English 📄 论文 • 🏆 排行榜 •🤗 数据集 简介CMMLU是一个综合性的中文评估基准,专门用于评估语言模型在中文语境下的知识和推理能力。CMMLU涵盖了...
Notably, CogVLM2 family has achieved state-of-the-art results on benchmarks like MMBench, MM-Vet, TextVQA, MVBench and VCGBench. All models are open-sourced in https://github.com/THUDM/CogVLM2 and https://github.com/THUDM/GLM-4, contributing to the advancement of the field. ...
What are the different kinds of match days at the venue? How do different factors affect stadium arrivals? Can we estimate the busyness of each gate, in order to better allocate staff and potentially homogenize it in future events? Our results show that it is informative to use this data fo...
Which results in another quaternion. If we replace the imaginary numbers ii, jj, and kk in the previous expression by the ordered pairs (also known as the quaternion units), i=[0,i] j=[0,j] k=[0,k]i=[0,i] j=[0,j] k=[0,k] And substituting back to the original expression ...
Evaluation Results Overview The closed-source proprietary model GPT-4o from OpenAI has taken a leading position in MMIU, surpassing other models such as InternVL2-pro, InternVL1.5-chat, Claude3.5-Sonnet, and Gemini1.5 flash. Note that the open-source models InternVL2-pro. ...
Paper tables with annotated results for CodeJudge-Eval: Can Large Language Models be Good Judges in Code Understanding?
Which results in another quaternion. If we replace the imaginary numbers ii, jj, and kk in the previous expression by the ordered pairs (also known as the quaternion units), i=[0,i] j=[0,j] k=[0,k]i=[0,i] j=[0,j] k=[0,k] And substituting back to the original expression ...
Which results in another quaternion. If we replace the imaginary numbers ii, jj, and kk in the previous expression by the ordered pairs (also known as the quaternion units), i=[0,i] j=[0,j] k=[0,k]i=[0,i] j=[0,j] k=[0,k] And substituting back to the original expression ...