int j = *(int*)i失败的原因（虽然使用void *pointer = &i;时语法是正确的）是因为您让所有线程...
int在main()中的每次循环迭代中更改值，而不告诉线程它正在更改。更糟糕的是，循环一结束，int的生存...
标准c（iso/iec 9899）和标准c++（iso/iec 14882）都定义了这个类型，请包含stdint.h（或cstdint在c++中）头文件。有些编译器不符合标准，可能没有这些头文件。这个类型实质上就是“无符号与指针空间等宽度整型”
直接强制转换为uint32_t可能会隐藏转换不可逆的事实。（不过，老实说，我想不出一个实现会导致这种情况。
直接强制转换为uint32_t可能会隐藏转换不可逆的事实。（不过，老实说，我想不出一个实现会导致这种情况...
c 1个回答 0投票 标准没有说明指向 void 的指针如何转换为 uintptr_t。 以下类型指定无符号整数类型任何指向 void 的有效指针都可以转换为此类型的属性,然后转换回指向 void 的指针,结果将进行比较等于原来的指针 您假设转换后的 uintptr_t代表物理地址。这个假设是错误的。编译器在转换期间可以自由地执行...
A void * in C has the huge advantage that it converts to/from other object pointer types without casts, which is way clean. That said uintptr_t might make sense if you want to do things to the bits of the pointer that you can't do as sensibly with a signed integer (such as ...
0xc0000d40d0 0xc0000d40d8 0xc0000d4150 unsafe package - unsafe - pkg.go.dev https://pkg.go.dev/unsafe https://pkg.go.dev/unsafe 非类型安全指针 - Go语言101(通俗版Go白皮书) https://gfw.go101.org/article/unsafe.html (1) Conversion of a *T1 to Pointer to *T2. ...
C.makeCurrentContext(C.uintptr_t(w.ctx))// Starting in OS X 10.11 (El Capitan), the vertex array is// occasionally getting unbound when the context changes threads./// Avoid this by binding it again.C.glBindVertexArray(C.GLuint(vba))iferrno := C.glGetError(); errno !=0{panic...
C.makeCurrentContext(C.uintptr_t(w.ctx))// Starting in OS X 10.11 (El Capitan), the vertex array is// occasionally getting unbound when the context changes threads./// Avoid this by binding it again.C.glBindVertexArray(C.GLuint(vba))iferrno := C.glGetError(); errno !=0{panic...