将UINT32值转换为UINT8数组[4]的方法是通过位运算和移位操作来实现。具体步骤如下: 1. 首先,将UINT32值按照大端字节序(Big-Endian)进行拆分,即高位字节在前,低位字节在后...
char* arr) { arr[0] = (num >> 24) & 0xFF; arr[1] = (num >> 16) & 0xFF; arr[2] = (num >> 8) & 0xFF; arr[3] = num & 0xFF; arr[4] = '\0'; // Add null character to terminate the string } int main() { uint32_t number = 12345678; char charArray[8]; co...