generate TypeScript types from your Zod schema Installation npm install zod-to-ts zod typescript Usage import { z } from 'zod' import { zodToTs } from 'zod-to-ts' // define your Zod schema const UserSchema = z.object({ username: z.string(), age: z.number(), inventory: z.object...
import{z}from'zod';constAddressSchema=z.object({street:z.string(),city:z.string(),zipCode:z.string().length(5),});constvalidateAddress=(address:unknown)=>{try{constparsedAddress=AddressSchema.parse(address);console.log("Validation passed: ",parsedAddress);}catch(error){if(errorinstanceofz....
import { z } from "zod/v4"; const Player = z.object({ username: z.string(), xp: z.number() }); Parsing data Given any Zod schema, use.parseto validate an input. If it's valid, Zod returns a strongly-typeddeep cloneof the input. ...
[Typescript] Zod custom error message constBookingSchema=z.object({roomType:z.string(),dueDate:z.string({message:"invalid due date",}).date('date format is wrong'),numberOfGuests:z.number().min(1,"there must be at least one guest").max(4,"at most 4 guests are allowed"),price:z...
第一步是为Zod设定架构。 导入* as z from "zod"; const userSchema = z.object({ id: z.number(), name: z.string(), age: z.number().可选() }).严格模式(); 如果你之前使用过其他验证工具,比如yup或joi,你可能已经熟悉这种做法。Zod 提供了多个函数,例如object(),string(),每个函数都返回一...
在看到zod使用的时候,有发现,可以通过zod定义的schema直接推导出type: const UserSchema = z.object({ username: z.string().min(3).max(20), email: z.string().email(), password: z.string().min(8), }); type User = z.infer<typeof schema>; 请问,这样的场景下,是否可以使用此方式进行替换...
import z from 'zod';const schema = z.object({id: z.string({required_error: "ID is required",invalid_type_error: "ID must be a string"}),name: z.string({required_error: "Name is required",invalid_type_error: "Name must be a string"}),portfolio: z.string({required_error: "portf...
(f)=>f.toLowerCase());constserver=newMcpServer({name:"mcp-cli-server",version:"1.0.0",});// 使用 Zod 定义工具的输入模式server.tool("search_local_database",z.object({query:z.string()}),async({query})=>{console.log("Tool called with query:",query);constqueryTerms=query.toLower...
import { z } from "zod/v4"; const Player = z.object({ username: z.string(), xp: z.number() }); Given any Zod schema, use.parseto validate an input. If it's valid, Zod returns a strongly-typeddeep cloneof the input.
Zod Auth.js 不是介绍 tRPC 吗,怎么突然出现这么多技术栈。好吧,主要这些技术栈都与 typescript 相关,并且在 trpc 的示例应用中都或多或少使用到,因此也是有必要了解一下。 在线体验地址:TRPC demo End-to-end typesafe APIs(端到端类型安全)