}typeStringOrNumberFunc=(ns:string|number) =>void;letfunc:StringOrNumberFunc= fn;// 不能将类型“(x: string) => void”分配给类型“StringOrNumberFunc”。// 参数“x”和“ns” 的类型不兼容。// 不能将类型“string | number”分配给类型“string”。// 不能将类型“string | number”分配给类...
// 定义人的接口interface IPerson {readonly id: number;age: number;}interface IPerson {name: string;sex: string;}const person2: IPerson = {//报错id: 2,name: "tom",age: 20,};会有报错信息：Property 'sex' is missing in type '{ id: number; name: string; age: number; }' but ...
interface SquareConfig { color?: string; width?: number; [propName: string]: any; } 函数类型 除了用接口描述对象结构外,接口也可以描述函数类型。 interface SearchFunc { (source: string, subString: string): boolean; } let mySearch: SearchFunc; mySearch = function (source: string, subString: ...
lett1: [string,number] t1 = ['hello',10]// OK t1 = [10,'hello']// Error 当访问一个已知索引的元素,会得到正确的类型: console.log(t1[0].substring(1))// OK console.log(t1[1].substring(1))// Error, 'number' 不存在 'substring' 方法 枚举 enum类型是对 JavaScript 标准数据类型的一...
import { Project } from './Project'; import React from 'react'; function formatDescription(description: string): string { return description.substring(0, 60) + '...'; } interface ProjectCardProps { project: Project; } function ProjectCard(props: ProjectCardProps) { const { project } = ...
环绕字符串中唯⼀的子字符串 题目链接: 467...环绕字符串中唯一的子字符串 - 力扣(LeetCode) https://leetcode.cn/problems/unique-substrings-in-wraparound-string/description...算法原理 状态表示:以某一个位置为结...
(source:string,subString:string):boolean; } 采用函数表达式接口定义函数的方式时,对等号左侧进行类型限制,可以保证以后对函数名赋值时保证参数个数、参数类型、返回值类型不变。 #可选参数 functionbuildName(firstName:string,lastName?:string){ if(lastName){ ...
We used the substr() method to find the old substring.function replaceSubString( mainString: string, oldString: string, newString: string ): string { let tempString: string = ""; for (let i = 0; i < mainString.length; i++) { if (mainString.substr(i, oldString.length) === old...
// 函数类型 interface SearchFunc { (source: string, subString: string): boolean; } let mySearch: SearchFunc; mySearch = function(source: string, subString: string) { let result = source.search(subString); return result > -1; }
72 String regex = "<a.*?/a>"; 73 p = Pattern.compile(regex); 74 m = p.matcher(str); 75 while(m.find()){ 76 /*For a matcher m with input sequence s, 77 * the expressions m.group() and s.substring(m.start(), m.end()) ...