1.1 忽略 undefined 和 null 类型 1 2 3 4 5 6 function myFunc(maybeString:string| undefined |null) { // Type 'string | null | undefined' is not assignable to type 'string'. // Type 'undefined' is not assignable to type 'string'. constonlyString:string= maybeString;// Error constigno...
Actual behavior: src/application-insights/ApplicationInsights.ts(25,17): error TS2722: Cannot invoke an object which is possibly 'undefined'. i.e. it believes thatappInsights(orai) is undefined even inside a check to prevent it from being undefined. Thanks in advance. Related Issues: Related ...
2. 调用函数时忽略 undefined 类型 type NumGenerator = () => number; function myFunc(numGenerator: NumGenerator | undefined) { // Object is possibly 'undefined'.(2532) // Cannot invoke an object which is possibly 'undefined'.(2722) const num1 = numGenerator(); // Error const num2 = n...
(2)、函数调用时忽略 null 和 undefined AI检测代码解析 type CallBackString = () => string; function test(call: CallBackString |null| undefined) { // Object is possibly 'undefined'. // Cannot invoke an object which is possibly 'undefined'. const onlyStringName = call(); // Error const ...
1031 错误 '{0}' modifier cannot appear on a class element. “{0}”修饰符不能出现在类元素上。1034 错误 'super' must be followed by an argument list or member access. "super" 的后面必须是参数列表或成员访问。1035 错误 Only ambient modules can use quoted names. 仅环境模块可使用带引号的...
(1)object 类型是:TypeScript 2.2 引入的新类型,它用于表示非原始类型。也就是除number,string,boolean,symbol,null或undefined之外的类型。 使用object类型,就可以更好的表示像Object.create这样的API。例如: declare function create(o:object|null):void; ...
//null 和 undefined 赋值给 boolean letisDone:boolean=false; isDone=null isDone=undefined "strictNullChecks":true #其他类型 #Array 对数组类型的定义有两种方式: letarr:string[]=["1","2"]; letarr2:Array<string>=["1","2"]; 定义联合类型数组 ...
TypeScript 里,undefined和null两者有各自的类型分别为undefined和null。 默认情况下null和undefined是所有类型的子类型。 就是说你可以把null和undefined赋值给number类型的变量。然而,如果你指定了--strictNullChecks标记,null和undefined只能赋值给void和它们各自的类型。
2366 错误 Function lacks ending return statement and return type does not include 'undefined'. 2368 错误 Type parameter name cannot be '{0}' 类型参数名称不能为“{0}” 2369 错误 A parameter property is only allowed in a constructor implementation. 只允许在构造函数实现中使用参数属性。
type CallBackString = () => string;function test(call: CallBackString |null| undefined) {// Object is possibly 'undefined'.// Cannot invoke an object which is possibly 'undefined'.const onlyStringName = call(); // Errorconst ignoreUndefinedAndNullName = call!(); //OK} ...