for...of 允许你遍历 Arrays(数组), Strings(字符串), Maps(映射), Sets(集合)等可迭代的数据结构等。 TypeScript for...of 循环 letsomeArray=[1,"string",false];for(letentryofsomeArray){console.log(entry);//1, "string", false} forEach、every 和 some 是 JavaScript 的循环语法,TypeScript ...
遍历// 对于int型数组int arrays[] = {1,2,3,4,5,4,3,2,1}; for(int temp : arrays) { System.out.println(temp...使用Arrays类的方法 // 对于int型数组int arrays[] = { 1,2,3,4,5,4,3,2,1}; System.out.println(Arrays.toString(...arrays)); 另外,如果是list,还可以考虑使用迭代器...
首先将其转换为字符串。虽然不确定typescript是否能够遵循这一点。https://developers.google.com/web/up...
// 'arr' gets value { length: 6 } const arr = minimumLength([1, 2, 3], 6); // and crashes here because arrays have // a 'slice' method, but not the returned object! console.log(arr.slice(0)); 指定类型参数 TypeScript 通常可以在泛型调用中推断出预期的类型参数,但并非总是如此。
允许你遍历 Arrays(数组), Strings(字符串), Maps(映射), Sets(集合)等可迭代的数据结构等 let someArray = [1,"string",false];for(let entry of someArray) { console.log(entry);//1, "string", false} while 一般用于未知循环次数 varnum =5;varfactorial =1;while(num >=1) { ...
可以使用for...of循环遍历 Map 对象的键值对。例如: 代码语言:typescript AI代码解释 letmap:Map<string,number>=newMap([['apple',5],['banana',8]]);for(let[key,value]ofmap){console.log(`${key}:${value}`);} 上述代码使用for...of循环遍历了 Map 对象中的键值对,并打印出每个键值对的内容...
constarr: ReadonlyArray<string> = ['foo','bar'];constcopy = arr.slice().sort(); Here we use 'ReadonlyArray<T>' to tell Typescript, this is a readonly array of string type. So IDE will tell you if you try to mutate the array. ...
When working with TypeScript applications, I find myself comparing strings almost daily. A few examples of when I was comparing strings include sorting arrays, validating user input, or checking conditions in my code. What seems like a simple operation actually has several nuances that can trip ...
Arrays in TypeScript can contain elements of the same type or a combination of different types. We can declare an array using square brackets, and the elements are separated by commas. Example 1 Open Compiler let numbers: number[] = [1, 2, 3, 4, 5]; let fruits: string[] = ["...
varfruitsArray:string[]=['apple','orange','lichi','orange','banana'];vartargetFruit:string='orange';varfoundIndices:number[]=[];letidx:number=fruitsArray.indexOf(targetFruit);while(idx!==-1){foundIndices.push(idx);idx=fruitsArray.indexOf(targetFruit,idx+1);}console.log(foundIndices); ...