classSolution{public:vector<int>twoSum(vector<int>& numbers,inttarget){/* Time exceeded code int i = 0; int len = 0; vector<int>ret; for(auto it = numbers.begin(); it != numbers.end(); ++it){ int another = targe
解法二:HashMap求解 对于一些了解HashMap这种数据结构的同学,很容易能想到利用HashMap来求解,也就是和LeetCode第一题TwoSum相同的解法 classSolution{publicint[]twoSum(int[]numbers,inttarget){Map<Integer,Integer>map=newHashMap<>();for(inti=0;i<numbers.length;i++){// map.put(numbers[i], i); /...
You may assume that each input would have exactly one solution and you may not use the same element twice. 给定一个已经按升序排序的整数数组,找到两个数字,使它们相加到一个特定的目标数。 函数twoSum应该返回两个数字的索引,使它们相加到目标,其中index1必须小于index2。 请注意,您返回的答案(index1和...
AC代码: classSolution {publicint[] twoSum(int[] numbers,inttarget) {int[] ans =newint[2];for(inti = 0; i < numbers.length - 1; i++) {//System.out.println(numbers[i]);intindex = binarySearch(numbers, i + 1, numbers.length - 1, target-numbers[i]);if(index != -1) { ans...
每天一算:Two Sum II leetcode上167号问题:Two Sum II 给定一个已按照升序排列 的有序数组,找到两个数使得它们相加之和等于目标数。 函数应该返回这两个下标值 index1 和 index2,其中 index1 必须小于 index2。 说明: 返回的下标值(index1 和 index2)不是从零开始的。
1. Two SumEasy Topics Companies Hint Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target. You may assume that each input would have exactly one solution, and you may not use the same element twice. You can return ...
LeetCode中关于双指针的题目有以下三种类型题: (一)双指针之左右指针相关题目: (二)双指针之快慢指针相关题目: (三)双指针之后序指针相关题目: (一)双指针之左右指针相关题目: 167. Two Sum II - Input array is sorted Given an array of integers that is already sorted in ascending order, find two ...
前言这道题和 leetcode 的第一道题非常类似,看起来非常简单。不过今天回头看,解法还是很多的。大概可以有下面几种:暴力解法 数组排序+二分 HashSet/HashMap 优化v1-暴力解法思路直接两次循环,找到符合结果的数据返回。这种最容易想到,一般工作中也是我们用到最多的。
leetcode No1:https://leetcode.com/problems/two-sum/ Given an array of integers,returnindices of the two numbers such that they add uptoa specific target.You may assume that each input would have exactly one solution,andyou may not use the same element twice.Example:Given nums=[2,7,11,...
声音简介 The two pointers pattern is a common technique used in many LeetCode problems to optimize the time and space complexity of algorithms, especially when dealing with arrays or strings. The idea is to use two distinct pointers that traverse the data structure, often from opposite ends or...