Two particles of equal masses moving with same momentum collide perfectly in-elastically. After the collision the combined mass moves with half of the speed of the individual masses. The angle between the initial momenta of individual particle is A60∘ B90∘ C120∘ D45∘Submit A particl...
The smallest ding-a-ling system consists of two particles of equal masses. They move along a ring, and interact via elastic collisions. One of them is bound by a harmonic potential. Here, the system is described by a set of coupled maps, which drive it from one collision of the ...
What is the position vector of centre of mass of two particles of equal masses ? View Solution Obtain an expression for the position vector of centre of mass of a two particle system. View Solution What is centre of mass of a body ? Obtain an expression for the positive vector of a cen...
The smallest ding-a-ling system consists of two particles of equal masses. They move along a ring, and interact via elastic collisions. One of them is bound by a harmonic potential. Here, the system is described by a set of coupled maps, which drive it from one collision of the particle...
We show that a system with two particles of equal masses and opposite electric charge on a plane subject to a constant magnetic field perpendicular to this plane is a completely integrable system. In the classical case, the separation of variables can be performed in oblate coordinates. In the...
6Two particles A and B, of masses mkg and lkg respectively, are connected by a light inextensible string of length dm and placed at rest on a smooth horizontal plane a distance of -dm apart. B is then projected horizontally with speed yms^{- in a direction perpendicular to AB.(a) Show...
6.P0Figure 2Two particles Pand Q have masses 0.1 kg and 0.5 kg respectively. The particles are attached to the ends of a light inextensible string. Particle P is held at rest on a rough horizontal table. The string lies along the table and passes over a small smooth pulley which is fix...
To find the moment of inertia of a system of two particles with masses m1 and m2 separated by a distance d about an axis passing through the center of mass and perpendicular to the line joining them, we can follow these steps: Step 1: Find the position of the center of mass (CM)The...
To find the position of the center of mass of two particles with given masses and positions, we can follow these steps:Step 1: Identify the masses and their positions - Let the mass \( mA = 1 \, \text{kg} \) be located at posit
First, the – 11 – formalism described in sections 2 and 3 for spinless particles of equal masses is well suited for NN scattering in spin-zero channels assuming the exact isospin symmetry. Secondly, because of the appearance of the strong long-range interaction due to the OPE, the NN ...