// Java Program to Convert LinkedHashMap to TwoArraysimportjava.io.*;importjava.util.*;classGFG{publicstaticvoidmain(String[] args){ LinkedHashMap<Integer, Integer> lhm =newLinkedHashMap<>(); lhm.put(2,6); lhm.put(3,4); lhm.put(5,7); lhm.put(4,6); lhm.put(6,8); Integer[]...
解法一:hashmap publicclassSolution {publicint[] intersect(int[] nums1,int[] nums2) { HashMap<Integer, Integer> map =newHashMap<Integer, Integer>(); ArrayList<Integer> result =newArrayList<Integer>();for(inti = 0; i < nums1.length; i++) {if(map.containsKey(nums1[i])) map.put(nu...
思路:偷懒一下,用Intersection of Two Arrays 的算法改动一下,看了下讨论,基本也是用hash,欢迎交流不同解法 public int[] intersect(int[] nums1, int[] nums2) { int len1 = nums1.length; int len2 = nums2.length; if(len1==0 || len2==0){ return new int[0]; } HashMap<Integer,Integer...
Given two arrays, write a function to compute their intersection. 爱写bug 2019/10/30 4530 两个数组的交集II 编程算法 遍历nums1并使用一HashMap存储每个元素出现的次数,接着遍历nums2,若当前元素在在map中出现次数大于0,则说明当前元素为交集记录该元素,将map中该数次数减1。 你的益达 2020/08/05 1.1K0...
349. Intersection of Two Arrays 349. Intersection of Two Arrays 【思路】 选择交叉元素; 利用set中元素的唯一性; 或者将两个排序,然后比较;...349. Intersection of Two Arrays My Submissions Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, ...
两个数组的交集 II intersection of two arrays ii 题目 分析 解答 题目 给定两个数组,编写一个函数来计算它们的交集。 示例 1: 示例 2: 说明: 输出结果中每个元素出现的次数,应与元素在两个数组中出现的次数一致。 我们可以不考虑输出结果的顺序。 进阶: 如果给定的数组已经排好序呢?你将如何优化你的算法?
Each element in the result should appear as many times as it shows in both arrays. The result can be in any order. Follow up: What if the given array is already sorted? How would you optimize your algorithm? What ifnums1's size is small compared tonums2's size? Which algorithm is ...
map.containsKey(nums1[i])){map.put(nums1[i],1);}else{map.put(nums1[i],map.get(nums1[i])+1);}}for(inti=0;i<length2;i++){if(map.containsKey(nums2[i])&&map.get(nums2[i])!=0){map.put(nums2[i],map.get(nums2[i])-1);ret[index++]=nums2[i];}}returnArrays.copyOf...
Map<Integer, Integer> map = new HashMap<Integer, Integer>(); //扫一遍数组,一边扫一边存 for(int i = 0; i < nums.length; i++){ int cur = nums[i]; //这里搞出来个差值,其实差值是在没找到之后添加到map里面的。 int toFind = target - cur; ...
简介:LeetCode之Intersection of Two Arrays 1、题目 Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. ...