Tuple assignment allows for a curious bit of idiomatic Python. Sometimes, when programming, you have two variables whose values you need to swap. In most programming languages, it’s necessary to store one of the values in a temporary variable while the swap occurs. Consider the following examp...
TypeError: 'tuple' object does not support item assignment 但是我们可以对tuple进行连接组合: >>> t1 = (1, 2, 3) >>> t2 =('a', 'b', 'c') >>> t3 = t1 + t2 >>> t3 (1, 2, 3, 'a', 'b', 'c') tuple中的元素为可变的数据类型,从而使tuple“可变”: >>> t = (1, 2,...
python复制代码# 这将引发一个TypeError，因为元组是不可变的。 my_tuple[0] = 10 # TypeError: 'tuple' object does not support item assignment 如果需要修改元组的内容，可以创建一个新的元组。元组的应用场景 当数据不应被修改时，例如常量集或预定义的配置。当需要在函数之间安全地传递数据时，因为元组是...
my_tuple=(1,2,3)my_tuple[0]=10# 这行代码会导致错误,因为元组不可变###Traceback(mostrecentcalllast):File"Untitled-1.py",line2,in<module>my_tuple[0]=10# 这行代码会导致错误,因为元组不可变TypeError:'tuple'objectdoesnotsupportitemassignment 添加和删除元素是不允许的:与列表(list)不同,元组不...
(most recent call last)<ipython-input-13-3c8e12ad4afd> in <module>---> 1 t1[0] = 100TypeError: 'tuple' object does not support item assignmentIn [15]: t2 = (1, 3)In [16]: t3 = t1 + t2In [17]: t3Out[17]: ('a', 'b', 1, 3)6 删除元组元组中的元素值是不允许删除...
>tuple1=(1,2,3,4,5,6)>>>tuple1(1,2,3,4,5,6)>>>tuple1[3]4>>>tuple1[3:](4,5,6)>>>tuple1[::-1](6,5,4,3,2,1)>>>tuple1[2]=6Traceback(most recent call last):File"<pyshell#15>",line1,in<module>tuple1[2]=6TypeError:'tuple'objectdoesnotsupport item assignment...
= 1) { Py_XDECREF(newitem); PyErr_BadInternalCall(); return -1; } if (i < 0 || i >= Py_SIZE(op)) { Py_XDECREF(newitem); PyErr_SetString(PyExc_IndexError, "tuple assignment index out of range"); return -1; } p = ((PyTupleObject *)op) -> ob_item + i; olditem =...
# tup1[0] = 100 这样修改元组元素操作是非法的,会报错(TypeError: 'tuple' object does not support item assignment) # 创建一个新的元组:两个元组连接起来 tup3 = tup1 + tup2 print (tup3) 运行结果: (12, 34.56, 'abc', 'xyz')
t = ('a','b','c','d','e')t[2] ='w'''TypeError: 'tuple' object does not support item assignment''' **拼接: + ** 虽然元组无法原地修改其中的元素,但是,通过+号可以把两个元组合并为一个新的元组。 t1 = ('a','b')t2 = ('c','d','e')t3 = t1 + t2print(t3)# ('a',...
append("张三") #不允许添加:tuple' object has no attribute 'append' tu[0] = "日元" #不允许修改 :object does not support item assignment del tu[2] #报错,不允许删除:'tuple' object doesn't support item deletion print(tu[2]) #索引就可以 #欧元 #关于元组不可变的注意点...