Can you solve this real interview question? Trips and Users - Table: Trips +---+---+ | Column Name | Type | +---+---+ | id | int | | client_id | int | | driver_id | int | | city_id |
[LeetCode] Trips and Users 旅行和用户 TheTripstable holds all taxi trips. Each trip has a unique Id, while Client_Id and Driver_Id are both foreign keys to the Users_Id at theUserstable. Status is an ENUM type of (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’). +...
City_Idint, Status ENUM('completed','cancelled_by_driver','cancelled_by_client'), Request_at varchar(50))2Create table If Not Exists Users (Users_Idint, Banned varchar(50), Role ENUM('client','driver','partner'))3Truncate table Trips4insert into Trips (Id, Client_Id, Driver_Id, Cit...
262 Trips and Users Leetcode mysql 262 Trips and Users 题目 解答 FBI Warning 注解 enum between count if round || truncate in 关于引号 大小写 题目 goto: leetcode 262 难度: Hard 解答 FBI Warning 这道题的描述是有问题的,leetcode上的题目也像是被更改过. “Write ......
The Users table holds all users. Each user has an unique Users_Id, and Role is an ENUM type of (‘client’, ‘driver’, ‘partner’). Table: Users 二、题目信息 找出2013年10月1日至2013年10月3日期间,每一天 未被禁止的 (unbanned) 用户的订单取消率。
Can you solve this real interview question? Trips and Users - Table: Trips +---+---+ | Column Name | Type | +---+---+ | id | int | | client_id | int | | driver_id | int | | city_id |
select*fromTrips a, Users bwherea.Client_Id=b.Users_Idandb.Role='client'andb.Banned='No'andRequest_atbetween'2013-10-01'and'2013-10-03'orderbyRequest_at; 2.依次遍历所有符合条件的记录,引入中间遍历@day(当前记录的日期),@lastday(上一条记录的日期),@snum(完成的记录数),@cnum(被取消的...
TheTripstable holds all taxi trips. Each trip has a unique Id, while Client_Id and Driver_Id are both foreign keys to the Users_Id at theUserstable. Status is an ENUM type of (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’). ...
TheTripstable holds all taxi trips. Each trip has a unique Id, while Client_Id and Driver_Id are both foreign keys to the Users_Id at theUserstable. Status is an ENUM type of (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’). ...
262. Trips and Users Method 1: SELECT t.Request_at AS Day, ROUND(SUM(IF(t.Status = 'completed',0,1)) / COUNT(*) ,2) AS 'Cancellation Rate' FROM Trips t INNER JOIN Users u ON t.Client_Id = u.Users_Id AND u.Banned = 'No'...