(v) so that the second line connect to the side of the triangle with a 90 degree angle. So I need to get this line, by calculate v with the data I got like shown below The angle of the triangle(30 degrees here). Will always be 90 degrees or under. As a...
在\triangle{ABC} 中,\angle{C} =90\degree,\angle{A}、\angle{B}、\angle{C}的对边分别是a、b、c。 (1)若a=3,b=4,则c= (2)若b=5,c=13,则b= (3)若b=2,c=3,则a=相关知识点: 试题来源: 解析 (1)5; (2)12; (3)\root \of {5}。 (1)若a=3,b=4,则c=\root \of {...
A right-angled triangle has one 90-degree angle. 5 Square A regular quadrilateral with four equal sides and angles. The game board for chess is a square with equal-sized squares. 8 Triangle Represents change or hazard in signs. Warning signs on the road often have a triangular shape. 5 ...
In trigonometry, the six trigonometric functions namely sine (sin), cosine (cos), tangent (tan), cosecant (csc), secant (sec), and cotangent (cot), each indicates a ratio of the length of two sides with respect to an angle of...
Unlike an equilateral triangle with its three equal sides and angles, an isosceles one with its two equal sides, or a right triangle with its 90-degree angle, a scalene triangle has three sides of random lengths and three random angles. If you want to know its area, you need to make a...
作\angle{BAC}的角平分线,交BC于点D 取AB的中点E连结DE,如图所示 辅助线AD和DE将Rt\triangle{ABC} 分割成3个全等的三角形 本题考查的是角平分线的性质,特殊角。 在这里\angle{C} =90\degree,\angle{B} =30\degree,所以\angle{BAC}=60\degree 因为要构造全等三角形 因此想到取\angle{BAC}的角平...
因为\angle ACB=90\degree,所以\overrightarrow{CB}\cdot\overrightarrow{CA}=0,又因为\overrightarrow{BM}=2\overrightarrow{MA},所以\overrightarrow{CM}=\overrightarrow{CB}+\overrightarrow{BM}=\overrightarrow{CB}+{2\over3}\overrightarrow{BA}=\overrightarrow{CB}+{2\over3}(\overrightarro...
如图,在\triangle{ABC} 中,\angle{C} =90\degree,c=1,则a^2+b^2+c^2=___。相关知识点: 试题来源: 解析 2 本题主要考查直角三角形的性质。 因为\angle{C} =90\degree, 所以a^2+b^2=c^2=1, 则a^2+b^2+c^2=2。 故本题正确答案为2。
\triangle ABC 中,\angle A、\angle B、\angle C 所对的边分别是a、b、c,且\angle C=90\degree ,a=9,b=12
(1)因为\angle{C} =90\degree,a=3,b=4 ,所以由直角三角形勾股定理c=\root \of {a^2+b^2} =5。故答案为5。 (2)因为\angle{C} =90\degree, c=13,b=5,所以由直角三角形勾股定理a=\root \of {c^2-b^2} =12。故答案为12。 (3)因为\angle{C} =90\degree, c=17,a=15,所以...